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3 years ago

Help me to answer this please

Mathematics

1 answer:

Ksju [112]3 years ago

3 0

The correct answer to your question is C. (I think, I'm pretty sure)

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Henry ran 1 5/8 miles in the morning and 9/10 in the afternoon . About how many miles did he run in all

arlik [135]

61/40, or about 2 and a half miles.the exact number is 2.525. hope this helps.

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3 years ago

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The volume of the right triangular prism is 91.8ft. The height of the prism is 10.8ft. What is the area of each base? Show your

kaheart [24]

Answer:

8.5 ft.

Step-by-step explanation:

We'll use this right triangular prism volume formula: base area x height = volume

base area = ?

length = 10.8

volume = 91.8

base area x 10.8 = 91.8

Divide both sides by 10.8

base area x 10.8/10.8 = 91.8/10.8

base area = 8.5

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2 years ago

-5=-10+ find the missing value

liraira [26]

Answer:

the missing values is 5

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3 years ago

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Ryan invested $5,900 in an account paying an interest rate of 5% compounded

vladimir1956 [14]

Answer:

10214.51

Step-by-step explanation:

5900 * (1+ (0.05/12))^(12*11)

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2 years ago

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What is the area of the trapezoid shown? trapezoid A = ______ units²?

notka56 [123]

Answer:

74.1 units²

Step-by-step explanation:

Area of the trapezoid shown = ½×(AD + BC)×BE

Use distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ to find AD, BC, and BE.

✍️Distance between A(-9, 4) and D(9, 1):

$AD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(9 -(-9))^2 + (1 - 4)^2}$

$= \sqrt{(18)^2 + (-3)^2}$

$= \sqrt{(324 + 9} = \sqrt{333}$

$AD = 18.2 units$ (nearest tenth)

✍️Distance between B(-4, -3) and C(2, -4):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(2 -(-4))^2 + (-4 -(-3))^2}$

$= \sqrt{(6)^2 + (-1)^2}$

$= \sqrt{(36 + 1} = \sqrt{37}$

$BC = 6.1 units$ (nearest tenth)

✍️Distance between B(-4, -3) and E(-3, 3):

$BE = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(-3 -(-4))^2 + (3 -(-3))^2}$

$= \sqrt{(1)^2 + (6)^2}$

$= \sqrt{(1 + 36} = \sqrt{37}$

$BE = 6.1 units$ (nearest tenth)

✔️Area of the trapezoid:

Area = ½×(AD + BC)×BE

Plug in the values into the formula

Area = ½×(18.2 + 6.1)×6.1

Area = ½×(24.3)×6.1

Area = 74.115 ≈ 74.1 units² (nearest tenth)

5 0

2 years ago