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Lelechka [254]
3 years ago
11

What is the answer to this question? Please Help.

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
5 0

Answer:

x = 2, y= 3

Step-by-step explanation:

y = -2x+7

y = 5x-7

Since the equations are both equal to y, set them equal to each other

-2x+7 = 5x-7

Add 2x to each side

-2x+7 +2x= 5x+2x-7

7 = 7x -7

Add 7 to each side

7+7 = 7x

14 = 7x

Divide by 7

14/7 = 7x/7

2 = x

Now find y

y = 5x-7

y = 5*2 -7

y = 10-7

y =3

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<u>First question answer:</u> The limit is 69

<u>Second question answer:</u> The limit is 5


Step-by-step explanation:

For the first limit, plug in x=8 in the expression (9x-3), that's the answer for linear equations and limits.

So we have:

9x-3\\9(8)-3\\72-3\\69

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For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value x=1 into the simplified expression to get the correct answer. Shown below:

\frac{x^2+8x-9}{x^2-1}\\\frac{(x+9)(x-1)}{(x-1)(x+1)}\\\frac{x+9}{x+1}

<em>Now putting 1 in x gives us the limit:</em>

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