Answer:
it is A
Step-by-step explanation:
it has to be a because you cant have a negative chance at chosing something it would just be zero B.you have a 1.00 chance at chosing something C.you have a 1 oit of 100 chance at chosing something and D.you have a 1 out of 10 chance at chosing something
Answer: her monthly payments would be $267
Step-by-step explanation:
We would apply the periodic interest rate formula which is expressed as
P = a/[{(1+r)^n]-1}/{r(1+r)^n}]
Where
P represents the monthly payments.
a represents the amount of the loan
r represents the annual rate.
n represents number of monthly payments. Therefore
a = $12000
r = 0.12/12 = 0.01
n = 12 × 5 = 60
Therefore,
P = 12000/[{(1+0.01)^60]-1}/{0.01(1+0.01)^60}]
12000/[{(1.01)^60]-1}/{0.01(1.01)^60}]
P = 12000/{1.817 -1}/[0.01(1.817)]
P = 12000/(0.817/0.01817)
P = 12000/44.96
P = $267
Rounding to the nearest thousand
for example, if the number is 104001. ten thousand would be 100000 while rounding to the nearest thousand would be 104000. accurate means closer to the correct answer, and the one rounded to the nearest thousand, 104000 is closer to the correct answer 104001 than the one rounded to ten thousand
Answer:
(x-1) (x+4)
Step-by-step explanation:
Factor x^2+3x-4 using the AC method
Answer: It is not possible that two triangles that are similar and not congruent in spherical geometry.
Step-by-step explanation:
For instance, taking a circle on the sphere whose diameter is equal to the diameter of the sphere and inside is an equilateral triangle, because the sphere is perfect, if we draw a circle (longitudinal or latitudinal lines) to form a circle encompassing an equally shaped triangle at different points of the sphere will definately yield equal size.
in other words, triangles formed in a sphere must be congruent and also similar meaning having the same shape and must definately have the same size.
Therefore, it is not possible for two triangles in a sphere that are similar but not congruent.
Two triangles in sphere that are similar must be congruent.
