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Ksenya-84 [330]
3 years ago
6

A series circuit contains two devices, one with a resistance of 10 ohms and one with a resistance of 4 ohms. If the generator su

pplies a voltage of 42 V, what is the magnitude of the current?
Physics
2 answers:
Harman [31]3 years ago
6 0
-- The net effective resistance of 10-ohms and 4-ohms
in series is 14 ohms.

-- The current in the series loop is  I = E/R = 42V/14-ohms = 3 amperes.

vladimir1956 [14]3 years ago
3 0
Total resistance = 10 + 4 = 14 ohms = 14Ω

Current = V/R

Current I = 42V / <span>14Ω =  3 Amperes.</span>
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