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nikdorinn [45]
3 years ago
9

Which of the following statements describes integrity? A. honesty regulated by a governmental regulatory committee B. honesty as

dictated by the school a person attends C. honesty regulated by a person’s sense of right and wrong D. honesty as dictated by an authority figure, like the president
Physics
1 answer:
dolphi86 [110]3 years ago
3 0

The correct answer is C. Honesty regulated by a person’s sense of right and wrong.

Explanation:

Integrity is a personal quality that encompasses moral and ethical correctness that allows an individual to be honest and behave appropriately in different situations and make decisions. This quality is closely related to morals and ethics because these two factors define what is right or wrong, and therefore determine the correct behaviors. Moreover, these factors might vary with the cultural context; for example, if culture emphasizes the importance of respecting the elderly any form of attack to this population would be considered as opposite to integrity. According to this, integrity is "Honesty regulated by a person’s sense of right and wrong."

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An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid C and 581 km from the center of asteroid
serg [7]

Answer:B

Explanation:

Given

Distance of astronaut From asteroid x is r_x=140 km

Distance of astronaut From asteroid Y is r_y=581 km

Suppose M,M_x,M_y be the masses of Astronaut , asteroid X and Y

If the astronaut is in equilibrium then net gravitational force on it is zero

F_x=F_y

\frac{GMM_x}{r_x^2}=\frac{GMM_y}{r_y^2}

cancel out the common terms we get

\frac{M_x}{r_x^2}=\frac{M_y}{r_y^2}

\frac{M_x}{M_y}=(\frac{r_x}{r_y})^2

\frac{M_x}{M_y}=(\frac{140}{581})^2

\frac{M_x}{M_y}=0.05806\approx 0.0581

8 0
3 years ago
A wheel rotates about a fixed axis with a constant angular acceleration of 4.0 rad/s2. The diameter of the wheel is 40 cm. What
Ray Of Light [21]

Answer:

v = 0.42m/s

Explanation:

In order o calculate the linear speed of the point at the border of the wheel, you first take into account that the total acceleration of such a point is given by:

a_{total}^2=a_r^2+a_t^2       (1)

atotal: total acceleration = 1.2m/s^2

ar: radial acceleration of the wheel

at: tangential acceleration

The tangential acceleration is also given by:

a_t=r\alpha     (2)

r: radius of the wheel = (40cm/2 )= 20cm = 0.2m

α: angular acceleration = 4.0rad/s^2

You replace the expression (2) into the expression (1) and solve for the radial acceleration:

a_{total}^2=a_r^2+(r\alpha)^2\\\\a_r=\sqrt{(a_{total})^2-(r\alpha)^2}\\\\a_r=\sqrt{(1.2m/s^2)^2-((0.2m)(4.0rad/s^2))^2}=0.894\frac{m}{s^2}

Next, you use the following formula for the radial acceleration and solve for the linear speed:

a_r=\frac{v^2}{r}\\\\v=\sqrt{ra_r}=\sqrt{(0.2m)(0.894m/s^2)}=0.42\frac{m}{s}

The linear speed of the point at the border of the wheel is 0.42m/s

5 0
3 years ago
A potter spins his wheel at 0.98 rev/s. The wheel has a mass of 4.2 kg and a radius of 0.35 m. He drops a chunk of clay of 2.9 k
Bad White [126]

Answer:

v_{f,w} = 1.791\,\frac{m}{s}, v_{f,c} = 0.972\,\frac{m}{s}

Explanation:

The situation can be modelled by applying the Principle of Angular Momentum Conservation:

I_{w} \cdot \omega_{o} = (I_{w} + I_{c})\cdot \omega_{f}

The final angular speed is:

\omega_{f} = \frac{I_{w}}{I_{w}+I_{c}}\cdot \omega_{o}

\omega_{f} = \left(\frac{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} }{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} + \frac{1}{2}\cdot (2.9\,kg)\cdot (0.19\,m)^{2}}\right)\cdot (0.98\,\frac{rev}{s} )\cdot \left(\frac{2\pi\,rad}{1\,rev}  \right)

\omega_{f} \approx 5.116\,\frac{rad}{s}

The tangential velocities of the wheel and the clay are, respectively:

v_{f, w} = (0.35\,m)\cdot (5.116\,\frac{rad}{s} )

v_{f,w} = 1.791\,\frac{m}{s}

v_{f, c} = (0.19\,m) \cdot (5.116\,\frac{rad}{s} )

v_{f,c} = 0.972\,\frac{m}{s}

5 0
3 years ago
How does heat reach to us from the sun<br><br><br>​
patriot [66]

Answer:

heat reaches to us from the sun through radiation since there is no medium in space, radiation is the major wat heat travels in space.

6 0
4 years ago
Which of the following processes could NOT be used to separate dissolved particles from the liquid in a solution? *
DIA [1.3K]

Answer:

Vaporation

Explanation:

In the vaporization or boiling, the passage of particles from the liquid state to the gaseous state occurs completely

5 0
4 years ago
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