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3 years ago

What should 6/54 be simplified

Mathematics

1 answer:

umka2103 [35]3 years ago

7 0

1/9
just divide 54 by 6 and you get 1/9

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F(x) = 9x-7. If f(x)= -7, find x.

svlad2 [7]

Answer: the answer is 56

Step-by-step explanation: since the f(x) is -7 it would be 9 times -7 then minus 7 and get the answer.

3 0

3 years ago

Jemina has 4 dogs, 8 cats and 12 fish as pets at her house.

eduard

Answer:

8:16

Step-by-step explanation:

6 0

2 years ago

1. Solve for x. Then find the angle measures of the triangle? (4x) (6x+55) (9x+30)

nalin [4]

Answer:

x = 5.

First angle = 20°, Second angle = 85°, Third angle = 75°

Step-by-step explanation:

The first angle of the triangle = (4 x)

The second angle of the triangle = (6x + 55)

The third angle of the triangle = (9x + 30)

By ANGLE SUM PROPERTY of a triangle:

First angle + Second angle + Third angle = 180°

⇒ (4 x) + (6x+55) + (9x+30) = 180°

or, (4x + 6x + 9x) + ( 55 + 30) = 180°

or, 19x = 180 - 85

or, 19 x = 95 ⇒ x = 95 /19 = 5

or, x = 5

Hence, first angle of the triangle = (4 x) = 4 x 5 = 20°

Second angle = ( 6x + 30) = 6(5) + 55 = 85°

Third angle = (9x + 30 = 9(5) + 30 = 75°

8 0

3 years ago

8x+20y=-120 as slope

Temka [501]

Answer:

y = -2/5x -6

slope is -2/5

y intercept -6

Step-by-step explanation:

8x+20y=-120

Slope intercept form is y = mx+b where m is the slope and b is the y intercept

Subtract 8x from each side

8x -8x+20y= -8x-120

20y = -8x - 120

Divide by 20

20y/20 = -8x/20 -120/20

y = -2/5x -6

3 0

3 years ago

Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)

Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

$x^{2} +y^{2}+4x-1=0$

Step-by-step explanation:

Explanation:-

Step 1:-

The equation of the circle having center and radius is

$(x-h)^2+(y-k)^2=r^2$

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

$(\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2} )$

$(-2,0)$

therefore center (h,k) = (-2,0)

Step 2:-

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

$\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}$

$r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}$

$r=\sqrt{5}$

Step 3:-

center (h,k) = (-2,0) and

radius $r=\sqrt{5}$

The standard form of circle equation

$(x-h)^2+(y-k)^2=r^2$

$(x-(-2))^2+(y-0)^2=\sqrt{5} ^2$

on simplification is

$x^{2} +y^{2}+4 x-1=0$

5 0

3 years ago