All categories

3 years ago

Find the unit rate. 55.9 meters in 13 seconds. Please help ASAP!

Mathematics

1 answer:

lbvjy [14]3 years ago

5 0

Answer:

4.3 meters per second

Step-by-step explanation:

55.9 meters ÷ 13 seconds

We want a unit rate where

1 is in the denominator,

so we divide top and bottom by 13

You might be interested in

Twenty percent of the shoes in a factory are black. one shoe is chosen and replaced. a second shoe is chosen and replaced. then

viva [34]

The probability that none of the shoes are black is:

The probability of the shoe that black is: 0.2

The probability of the shoe that is not black is: 0.8

Black: 0.2

Not black: 0.8

Since we’re looking for the probability of the shoe that is not black and there are 3 in a row, the answer will be = 0.8^3

= 0.8^3 will give you the equivalent of 0.512

If changed in percent form, the answer will be: 51.2%

4 0

3 years ago

The quotient of five and seven

Gala2k [10]

Answer:

Decimal: 0.71428571428

Fraction: 5/7

Step-by-step explanation:

Quotient is just the result of a division problem so 5 and 7: 5/7

Decimal: 0.71428571428

Fraction: 5/7

7 0

4 years ago

Read 2 more answers

If f(x) = -2(5)^x , what if f(2)

BaLLatris [955]

Answer:

-50

Step-by-step explanation:

Put 2 where x is and do the arithmetic.

f(2) = -2(5^2) = -2(25) = -50

3 0

3 years ago

1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro

alex41 [277]

Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

$P(VISA \:| \:AE) = 15\%\\$

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

$P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}$

For the given problem it becomes

$P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}$

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

$P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\$

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

8 0

3 years ago

Identify the center and radius of a circle with equation (x+4)^2+(y-2)^2 =36

babymother [125]

Radius is 6 and centre is (-4,2)

8 0

3 years ago