All categories

3 years ago

Maggie's brother is 4 years younger than three times her age. The sum of their ages is 20. How old is Maggie?

Mathematics

1 answer:

makkiz [27]3 years ago

6 0

Maggie would be 6

6•3=18
18-4=14
14+6=20

You might be interested in

Acute angles Angles that measure 60°

3241004551 [841]

Acute angles are angles that measure below 90°, meaning below a right angle.

3 0

3 years ago

Read 2 more answers

Which expression makes the equation true?

valina [46]

Equation is y^20 = ( )^2

Answer:

y to the power of 10.

4 0

3 years ago

The carnival charges $5 admission and $0.50 for each ride. Alex's dad gave him $15 to spend. How many rides can he go on at most

Oxana [17]

Let us suppose number of rides is x.One ride costs $0.50.

Cost of x rides is 0.50x. The carnival charges is $5. Alex has $15 to spend .

Number of rides at most Alex can have can be given by the inequality:

0.50x+5≤ 15

To solve for x we subtract 5 both sides

0.50x≤ 15-5

0.50x≤ 10

Dividing both sides by 0.50 we have :

x≤ 20

Number of rides at most Alex can have is 20.

8 0

3 years ago

Read 2 more answers

Please help i am super confused on what to do :)

Ludmilka [50]

Answer:

About 9.1 yards tall.

Step-by-step explanation:

So, we can draw the right triangle shown below:

We want to find h.

Since we know the angle and the side adjacent to the angle and we wan to find the opposite side, we will use the tangent ratio:

$\displaystyle \tan(x^\circ)=\frac{\text{Opposite}}{\text{Adjacent}}$

So:

$\displaystyle \tan(20)=\frac{h}{25}$

Therefore:

$\displaystyle h=25\tan(20)$

Use a calculator. Ensure your calculator is in the correct mode (degrees mode):

$h\approx 9.1\text{ yards}$

The goal post is around 9.1 yards tall.

7 0

3 years ago

If f(x) = 1 + x2 and g(x) = 1-, which is the rule of function (f-)(x)?

STatiana [176]

Answer:

= -x^2 +x

Step-by-step explanation:

(x) = 1 - x^2

g(x) = 1-x,

(f-g)(x) = 1-x^2 - ( 1-x)

Distribute the minus sign

= 1-x^2 -1 +x

Combine like terms

= -x^2 +x

8 0

3 years ago