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Blababa [14]
2 years ago
11

Bob is on his way home in his car. His drive is 16 miles long. He has finished one-fourth of the drive so far. How far has he dr

iven?
Mathematics
1 answer:
Georgia [21]2 years ago
7 0

Answer:

He has driven 16 miles so far

Step-by-step explanation:

The unknown in your equation is the total length of Trey's drive, which we will call "x".

From the problem statement, you know that 12 is three-fourths of x so set up the following equation and solve for "x":

3/4(x) = 12

multiply both sides of the equation by 4/3 to isolate "x":

(4/3)(3/4)(x) = (12)(4/3)

therefore

x = (12)(4)/(3) = 16

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3 years ago
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :
const2013 [10]

Answer:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.

This means that n = 1067, \pi = \frac{74}{1067} = 0.069

80% confidence level

So \alpha = 0.2, z is the value of Z that has a pvalue of 1 - \frac{0.2}{2} = 0.9, so Z = 1.28.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 - 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.059

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 + 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.079

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

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2 years ago
Solve 8 = 2^x + 4.<br><br> A. x=-4<br> B. x=-1<br> C. x=0<br> D. x=7
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What is the distance between-10 and 16 on the number line
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the answer is 26 hope that helps


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