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Tpy6a [65]
3 years ago
13

Check all of the steps that would be used to solve this equation: 2(x-5)=24

Mathematics
1 answer:
aliya0001 [1]3 years ago
8 0
X=17

Distribute 2(x-5)
You are left with 2x-10=24
You then want to get 2x by itself so add 10 on both sides so that you get 2x=34
Isolate x completely by dividing by 2 on both sides which then leaves you with x=17
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Please help me quick :)
krek1111 [17]
It would be an average of about 8.00 (7.99 to be somewhat exact). You get this by dividing the total amount by 200, the dividing that by 363.
7 0
3 years ago
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What is minus 6 plus 2?<br><br><br> -4<br><br><br> 8<br><br><br> 4
schepotkina [342]

Answer:

-4

Step-by-step explanation:

-6+2=-4

3 0
3 years ago
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6) If 1 Inch = 2.54cm, then set up and solve a proportion that finds how many
Roman55 [17]

Answer:

3.93700787402, almost  4

Step-by-step explanation:

10 ÷ 2.54

3 × 2.50 = 7.50

3 × 0.04 = 0.12

7.50 + 0.12 = 7.65

7.65 + 2.54 = 10.19

The precise number is use calculator.

7 0
3 years ago
Two machines are used for filling plastic bottles to a net volume of 16.0 ounces. A member of the quality engineering staff susp
aleksandrvk [35]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if the two machines are filling the bottles with a net volume of 16.0 ounces or if at least one of them is different.

The parameter of interest is μ₁ - μ₂, if both machines are filling the same net volume this difference will be zero, if not it will be different.

You have one sample of ten bottles filled by each machine and the net volume of the bottles are measured, determining two variables of interest:

Sample 1 - Machine 1

X₁: Net volume of a plastic bottle filled by the machine 1.

n₁= 10

X[bar]₁= 16.02

S₁= 0.03

Sample 2 - Machine 2

X₂: Net volume of a plastic bottle filled by the machine 2

n₂= 10

X[bar]₂= 16.01

S₂= 0.03

With p-values 0.4209 (for X₁) and 0.6174 (for X₂) for the normality test and using α: 0.05, we can say that both variables of interest have a normal distribution:

X₁~N(μ₁;δ₁²)

X₂~N(μ₂;δ₂²)

Both population variances are unknown you have to conduct a homogeneity of variances test to see if they are equal (if they are you can conduct a pooled t-test) or different (if the variances are different you have to use the Welche's t-test)

H₀: δ₁²/δ₂²=1

H₁: δ₁²/δ₂²≠1

α: 0.05

F= \frac{S^2_1}{S^2_2} * \frac{Sigma^2_1}{Sigma^2_2} ~~F_{n_1-1;n_2-1}

Using a statistic software I've calculated the test

F_{H_0}= 1.41

p-value 0.6168

The p-value is greater than the significance level, so the decision is to not reject the null hypothesis then you can conclude that both population variances for the net volume filled in the plastic bottles by machines 1 and 2 are equal.

To study the difference between the population means you can use

t= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }  ~~t_{n_1+n_2-2}

The hypotheses of interest are:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

α: 0.05

Sa= \sqrt{\frac{(n_1-1)S^2_1+(N_2-1)S^2_2}{n_1+n_2-2}} = \sqrt{\frac{9*9.2*10^{-4}+9*6.5*10^{-4}}{10+10-2} } = 0.028= 0.03

t_{H_0}= \frac{(16.02-16.01)-0}{0.03*\sqrt{\frac{1}{10} +\frac{1}{10} } } = 0.149= 0.15

The p-value for this test is: 0.882433

The p-value is greater than the significance level, the decision is to not reject the null hypothesis.

Using a significance level of 5%, there is no significant evidence to reject the null hypothesis. You can conclude that the population average of the net volume of the plastic bottles filled by machine one and by machine 2 are equal.

I hope this helps!

8 0
3 years ago
Which is the distance between points A and B
natita [175]
Given A and B are points in nth dimensions.
E.g. (a1, a2, ..., an), (b1, b3, ..., bn)
The vector from point A to point B is given by B-A.
Taking the modulus or magnitude of this will give us the distance.
Therefore distance = || B-A ||
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