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zimovet [89]
2 years ago
14

What is the expected length of a sequence that is monotonically increasing when drawn from the distribution?

Mathematics
1 answer:
Wewaii [24]2 years ago
4 0
<span>First thing is to phrase the question in the notation of a probability. We are looking for - p(x1<x2,x3<x2) Next step is to simply expand this based on the rules of conditional probability as - p(x1<x2,x3<x2)=â«10p(x1<x2,x3<x2|x2)p(x2)dx2 Given we are working with uniform[0,1] variables, the first term can be written simply - p(x1<x2,x3<x2|x2)=x22 We also know that p(x2)=1 on the interval we care about. Therefore we have - p(x1<x2,x3<x2)=â«10x22dx2=x33âŁâŁâŁ10=1/3</span>
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Find the missing side length, and enter your answer in the box below. If
kondor19780726 [428]

Pythagorean theorem. A^2+B^2=C^2.

So 12^2+16^2=c^2

144+256=c^2

400=c^2

square root of 400=c

So C=20

Hit the heart if it was helpful :D

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2 years ago
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Distribute to write an equivalent expression: -1/2 (-2x+4y)
Triss [41]

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x - 2y

Step-by-step explanation:

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Find the value of the following expression:
Ira Lisetskai [31]

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4

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3 years ago
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the ride it store rents bicycles. the cost is $8.50 for 1 hour, $13.65 for 2 hours, $18.80 for 3 hours, and $23.95 for 4 hours.
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5 0
2 years ago
I need help with coming up with equation
Natali5045456 [20]

Let's call a child's ticket c and an adult's ticket a. From this, we can say:

c + a = 116,

since 116 tickets are sold in total.


Now, we are going to need to find another equation (the problem asks us to solve a systems of equations). This time, we are not going to base the equation on ticket quantity, but rather ticket price. We know that an adult's ticket is $17,000, and a child's ticket is thus

\$17000 \cdot (1 - \dfrac{1}{4}) = \$12750.


Given these values, we can say:

17000a + 12750c = 1653250,

since each adult ticket a costs 17,000 and each child's ticket c costs 12,750, and these costs sum to 1,653,250.


Now, we have two equations:

17000a + 12750c = 1653250

c + a = 116


Let's solve:

17000a + 12750c = 1653250

a = 116 - c

  • Find a on its own, which will allow us to substitute it into the first equation

17000(116 - c) + 12750a = 1653250

  • Substitute in 116 - c for a

1972000 - 17000c + 12750c = 1653250

  • Apply the Distributive Property

1972000 - 4250c = 1653250

  • Combine like terms

4250c = 318750

  • Subtract 1972000 from both sides of the equation and multiply both sides by -1

c = 75


We have now found that 75 child's tickets were sold. Thus,

75 + a = 116 \Rightarrow a = 116 - 75 = 41,

41 adult tickets were sold as well.


In sum, 41 adult tickets were sold along with 75 child tickets.

6 0
2 years ago
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