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3 years ago

What is the expected length of a sequence that is monotonically increasing when drawn from the distribution?

1 answer:

4 0

<span>First thing is to phrase the question in the notation of a probability. We are looking for - p(x1<x2,x3<x2) Next step is to simply expand this based on the rules of conditional probability as - p(x1<x2,x3<x2)=â«10p(x1<x2,x3<x2|x2)p(x2)dx2 Given we are working with uniform[0,1] variables, the first term can be written simply - p(x1<x2,x3<x2|x2)=x22 We also know that p(x2)=1 on the interval we care about. Therefore we have - p(x1<x2,x3<x2)=â«10x22dx2=x33âŁâŁâŁ10=1/3</span>

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1: Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not hav

OLga [1]

Answer:

(1) y=C, $C\neq0$

(2) x=C

(1) y=0

Step-by-step explanation:

For the linear equation, the power on the solitary variable must be 1.

When the graph of a function crosses/ touches the x-axis than the equation has solution/solutions otherwise it does not has a solution.

When it touches/cresses the x-axis for infinite times then it will have an infinite number of solutions.

(1) The linear equation y-C=0, where y is a variable and C is a non-zero constant, $C \neq 0$ , has the graph parallel to the x-axis. It has no solution as the graph will never cross/touch the x-axis.

Algebraically, in linear equation y-C=0, is independent of x, so there is no value of x for the solution to be exist.

(2) The linear equation x-C=0, where x is a variable and C is a constant, has one solution.

The solution for the equation is

x-C=0

$\Rightarrow x=C$ , where $C\neq0$ .

(3) The linear equation y=0, where y is a variable, has the graph coinciding with the x-axis. So, it has infinitely many solutions.

Algebraically, in linear equation y=0, is independent of x, so for all value of x, the given equation is zero. Hence, there are infinitely many solutions.

3 0

3 years ago

Factor the expression using GCF 9a + 15b ?

Aleksandr [31]

Answer:

3(3a+15b)

Step-by-step explanation:

GCF: 3

Find all the prime factors between 3 and 15

3: 1,3 1*3

15: 1,3,5,15 (1*15 3*5)

3 is the GCF between the 2 numbers.

6 0

2 years ago

The length of the rectangle is 5 inches more than the width. The perimeter of the rectangle is 42 inches. Write an equation to m

Sunny_sXe [5.5K]

Answer:

<h2>Length = 13 in. </h2>

Step-by-step explanation:

perimeter of a rectangle (P) = 2L + 2W

where;

P = 42 in.

Length (L) = 5 + W

Find:

length (L) of the rectangle

solution:

P = 2L + 2W

42 = 2(5 + W) + 2W

42 = 10 + 2W + 2W

42 - 10 = 4W

32 = 4W

W = 32/4

W = 8

Length (L) = 5 + W

= 5 + 8

= 13 in

proof:

42 = 2(13) + 2(8)

42 = 42 in

4 0

3 years ago

Which of the following inferences can you make?

maksim [4K]

Answer:a and d

Step-by-step explanation:

i did it

7 0

3 years ago

Read 2 more answers

Can I get some help plz thank u sm

weeeeeb [17]

Answer:

x = 72

hope it helps

5 0

2 years ago