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olga55 [171]
3 years ago
10

Patricia and Joe Payne are divorced. The divorce settlement stipulated that Joe pay $485 a month for their daughter Suzanne unti

l she turns 18 in 4 years. Interest is 6% a year. How much must Joe set aside today to meet the settlement?
Mathematics
1 answer:
zhuklara [117]3 years ago
3 0
\bf \qquad \qquad \textit{Future Value of an ordinary annuity}
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]

\bf \begin{cases}
A=
\begin{array}{llll}
\textit{original amount}\\
\textit{already compounded}
\end{array} &
\begin{array}{llll}

\end{array}\\
pymnt=\textit{periodic payments}\to &
\begin{array}{llll}
485\cdot 12\\
\underline{5280}
\end{array}\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{a year, thus once}
\end{array}\to &1\\

t=years\to &4
\end{cases}
\\\\\\


\bf A=5280\left[ \cfrac{\left( 1+\frac{0.06}{1} \right)^{1\cdot  4}-1}{\frac{0.06}{1}} \right]

Joe is making $485 payments monthly, but the amount gets interest on a yearly basis, not monthly, so the amount that yields interest is 485*12

also, keep in mind, we're assuming is compound interest, as opposed to simple interest
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The number of books sold over the course of the four-day book fair were 190, 100, 272, and 74. Assume that samples of size 2 are
g100num [7]

Answer:

the answer is below

Step-by-step explanation:

We have the total number of possible samples = 4 * 4 = 16 (As 4 choices for each value)

in addition we have to as all sample occur with equal probability, probability of each sample = 1/16, below is samling distribution of mean

x1 x2 probabilityP(x1,x2) sample mean

190 190    1/16                 190

190 100    1/16                 145

190 272    1/16                 231

190 74    1/16                 132

100 190    1/16                 145

100 100    1/16                 100

100 272    1/16                 186

100 74    1/16                        87

272 190    1/16                 231

272 100    1/16                 186

272 272    1/16                 272

272 74    1/16                 173

74 190    1/16                 132

74 100    1/16                 87

74 272    1/16                 173

74 74    1/16                 74

Summarizing above with adding duplicate values

sample mean   probability

       74              1/16

      87               1/8

    100                1/16

    132                1/8

    145                1/8

    173                1/8

   186                1/8

   190               1/16

    231               1/8

   272               1/16

5 0
3 years ago
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Answer:

a) (4x® - 5x + 15) - (11 - 7x - 2x)

b)(9x- 6x® - 7x-2) + (10x - 8x + 11)

Step-by-step explanation:

a) (4x® - 5x + 15) - (11 - 7x - 2x)

b)(9x- 6x® - 7x-2) + (10x - 8x + 11)

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