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VikaD [51]
3 years ago
6

Mrs. Daly's reading classes were surveyed about their reading preferences. The data is summarized in the table below.

Mathematics
1 answer:
andriy [413]3 years ago
5 0

Answer:

Required probability is 0.19

Step-by-step explanation:

The two-way table for the given data is,

                              Fiction                Non-Fiction                Total

9th grade                35                            8                             43

10th grade               52                            12                           64

Total                        87                            20                           107

It is required to find the probability of the students who prefer to read non-fiction novels, given that they are in 9th grade.

That is, to find the conditional probability P(Non-fiction| 9th\ grade).

Now, P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}

So, we get,

P(Non-fiction| 9th\ grade)=\dfrac{(Non-fiction\bigcap 9th\ grade)}{P(9th\ grade)}\\\\P(Non-fiction| 9th\ grade)=\dfrac{8}{43}\\\\P(Non-fiction| 9th\ grade)=0.19

<h3>Thus, the required probability is 0.19.</h3>
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100

Step-by-step explanation:

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So

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2 years ago
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MArishka [77]

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3 years ago
According to the College Board website, the scores on the math part of the SAT (SAT-M) in a recent year had a mean of 507 and st
Leviafan [203]

Answer:

The actual SAT-M score marking the 98th percentile is 735.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 507, \sigma = 111

Find the actual SAT-M score marking the 98th percentile

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2.054 = \frac{X - 507}{111}

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3 years ago
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