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2 years ago

Mrs. Daly's reading classes were surveyed about their reading preferences. The data is summarized in the table below.

Mathematics

1 answer:

andriy [413]2 years ago

5 0

Answer:

Required probability is 0.19

Step-by-step explanation:

The two-way table for the given data is,

Fiction Non-Fiction Total

9th grade 35 8 43

10th grade 52 12 64

Total 87 20 107

It is required to find the probability of the students who prefer to read non-fiction novels, given that they are in 9th grade.

That is, to find the conditional probability $P(Non-fiction| 9th\ grade)$ .

Now, $P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}$

So, we get,

$P(Non-fiction| 9th\ grade)=\dfrac{(Non-fiction\bigcap 9th\ grade)}{P(9th\ grade)}\\\\P(Non-fiction| 9th\ grade)=\dfrac{8}{43}\\\\P(Non-fiction| 9th\ grade)=0.19$

<h3>Thus, the required probability is 0.19.</h3>

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Answer:

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2 years ago

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telo118 [61]

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Ben and his three friends were ordering pizza. They could spend at most $26. If a large

lutik1710 [3]

Answer:

6 toppings

Step-by-step explanation:

The t in this equation represents the amount of toppings.

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2 years ago

A university knows from historical data that 25% of students in an introductory statistics class withdraw before completing the

Vikki [24]

Answer:

13.4%

Step-by-step explanation:

Use binomial probability:

P = nCr p^r q^(n-r)

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1-p).

Here, n = 16, r = 2, p = 0.25, and q = 0.75.

P = ₁₆C₂ (0.25)² (0.75)¹⁶⁻²

P = 120 (0.25)² (0.75)¹⁴

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There is a 13.4% probability that exactly 2 students will withdraw.

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3 years ago

Can someone help me with this asap please, thanks!

kvv77 [185]

Answer:

Given: $r\perp s$ and $t\perp s$ .

Prove: $r\parallel t$

Since $r\perp s$ , By the definition of perpendicular lines angles 1, 2, 3 and 4 are 90 degree. similarly $t\perp s$ , it means angles 5, 6, 7 and 8 are 90 degree.

We can say that,

$\angle 1\cong \angle 5$ , $\angle 2\cong \angle 6$ , $\angle 3\cong \angle 7$ and $\angle 4\cong \angle 8$

From figure it is noticed that the angle 1 and 5 are corresponding angles.

If two parallel lines are intersected by a transversal, then the corresponding angles are equal.

Since corresponding angles are congruent, therefore the line must be parallel to each other.

Hence proved that $r\parallel t$ .

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2 years ago