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slavikrds [6]
3 years ago
12

How to do double sided equations

Mathematics
1 answer:
Veronika [31]3 years ago
7 0

Answer:

multiply each side

Step-by-step explanation: this is becasue when numbers are beside eachother they mean multiply


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A football team has a budget of $2500 for supplies. The team purchased new helmets for $975. Each new football costs $34. The in
asambeis [7]

The correct answer is d) The maximum number of footballs the team can purchase is 44.

this is true because if we plug 44 into the equation it is the only value that is can fit into the equation without it becoming false.

975 + 34(44) ≤ 2500

2471 ≤ 2500

5 0
3 years ago
Read 2 more answers
375.1333 rounded to the nearest whole number
Oksi-84 [34.3K]
As 0.1333 is less than 0.5 the answer is


375
 
3 0
3 years ago
PROBLEM: Juan hires an electrician. Juan pays a one-time fee of $30. Juan also pays $45 for each hour the electrician works. A.
PolarNik [594]

Answer:

A: C=45h+30

B: C=$322.50

Step-by-step explanation:

A: We'll start with the equation for the total charge. Juan is saying he will pay a one time fee of $30, meaning there is 30 dollars added to what ever the hourly wage is. This can be represented by the +30. Now if "h" represents the variable for which the hourly wage will be calculated, and he pays $45 dollars per hour this will be represented as 45h. <em>As an example if I pay you 2 dollars per hour using the same variable "h", this would be represented as 2h. So if you worked for two hours you would get 4 dollars, this is proven by the fact the 2(2) (remeber im replacing the "h" with the hours you worked) obviously 2 times 2 is 4 proving my point. </em>This information will give you the equation you see above.

B: Onto solving for how much Juan will pay. Now you say youre supposed to have 9 answer but this can't be true. All you need to do is plug the hours given into "h" and solve the equation. It should look something like:

<u>C=45h+30</u>

<u>C=45(6.5)+30</u>

Im using a decimal because it should be clear 1/2=0.5

<u>C= 292.5+30</u>

45x6.5 always go with PEMDAS, we are multiplying first. Then add 292.5 plus 30

This results in the answer of:

<u>C=$322.50</u>

3 0
3 years ago
An adult brain is about 140 mm wide and divided into two sections (called "hemispheres" although the brain is not truly spherica
Sedbober [7]

Answer: 3.61×10^5 A

Step-by-step explanation: Since the brain has been modeled as a current carrying loop, we use the formulae for the magnetic field on a current carrying loop to get the current on the hemisphere of the brain.

The formulae is given below as

B = u×Ia²/2(x²+a²)^3/2

Where B = strength of magnetic field on the axis of a circular loop = 4.15T

u = permeability of free space = 1.256×10^-6 mkg/s²A²

I = current on loop =?

a = radius of loop.

Radius of loop is gotten as shown... Radius = diameter /2, but diameter = 65mm hence radius = 32.5mm = 32.5×10^-3 m = 3.25×10^-2m

x = distance of the sensor away from center of loop = 2.10 cm = 0.021m

By substituting the parameters into the formulae, we have that

4.15 = 1.256×10^-6 × I × (3.25×10^-2)²/2{(0.021²) + (3.25×10^-2)²}^3/2

4.15 = 13.2665 × 10^-10 × I/ 2( 0.00149725)^3/2

4.15 = 1.32665 ×10^-9 × I / 2( 0.000058)

4.15 × 2( 0.000058) = 1.32665 ×10^-9 × I

I = 4.15 × 2( 0.000058)/ 1.32665 ×10^-9

I = 4.80×10^-4 / 1.32665 ×10^-9

I = 3.61×10^5 A

3 0
3 years ago
I got a screenshot, You got answer
liq [111]

Answer:

A. V = (pi)(3.25)^2(12)

Step-by-step explanation:

The formula for the volume of a cylinder is the formula for the area of the circle, times the height of the cylinder. The formula for the volume of a circle is,

A = (pi)(r)^2

Multiply that by the height to find the formula for the volume of a cylinder,

V=(pi)(r)^2(h)

Where (pi) represents the value (3.1415), (r) represents the radius, and (h) represents the height of the cylinder. Now substitute in the given values, remember, this problem gives the diameter of the cylinder, divide that value by two to find the radius.

V=(pi)(\frac{6.5}{2})^2(12)\\\\V = (pi)(3.25)^2(12)

3 0
3 years ago
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