52 = 50
512= 500
500/50 = 10
Answer:
7/8 > 5/6
Step-by-step explanation:
A) 7/8
We can compare this as follows.
Lets say both are equal.
Cross multiplying these we get 40=42
We get 40<42. In fraction we get
In case if you want to convert this to decimal, we get;
5/6 = 0.833 and 7/8 = 0.875
We get 5/6<7/8
B) 4/5
Similarly we get 4/5 = 0.8 and 5/6 = 0.833
Here 4/5<5/6
C) 3/4
we get 3/4 = 0.75 and 5/6 = 0.833
3/4<5/6
D) 2/3
we get 2/3 = 0.66 and 5/6 = 0.833
2/3<5/6
Step-by-step explanation:
Answer:
45231 = 
Step-by-step explanation:
Given the number:
45,231
We have To write the given number in the expanded form.
Solution:
First of all, let us write the different digits of the number:
Unit's digit = 1
Ten's digit = 3
Hundred's digit = 2
Thousand's digit = 5
Ten thousand's digit = 4
Unit's digit has to be multiplied with 1.
Ten's digit has to be multiplied with 10.
Hundred's digit has to be multiplied with 100.
Thousand's digit has to be multiplied with 1000.
Ten Thousand's digit has to be multiplied with 10000.
And then they have to be added so that the number gets formed.
45231 =
Note that x² + 2x + 3 = x² + x + 3 + x. So your integrand can be written as
<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>
<span>Next, complete the square. </span>
<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>
<span>Also, for the x in the numerator </span>
<span>x = x + 1/2 - 1/2. </span>
<span>So </span>
<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>
<span>Integrate term by term to get </span>
<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>
<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>
<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>
<span>= 2 √(x) ln(x) - √(x) + C. </span>
<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>
<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>
<span>= arctan(e^x) + C.</span>
