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4 years ago

Can someone help me this is really confusing????? What is the solution set for the open sentence with the given replacement set?

Mathematics

1 answer:

IgorLugansk [536]4 years ago

6 0

The answer is:

w^2 - 1 = w + 5

3^2 - 1 = w + 5

3^2 = 3(3) = 9

9-1 = 8

8 = 3 + 5

8 = 8

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Hurry 50 points for correct answer

Ad libitum [116K]

Answer: <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>

Step-by-step explanation:

The equation $x=\sqrt{6x+7}$ can be solved by squaring both sides:

$x^2 = 6x + 7\\\\x^2 - 6x - 7 = 0\\\\(x-7)(x+1) = 0$

We can see that -1 and 7 are solutions, but make sure they are not extraneous by substituting them in the original equation:

$1 = \sqrt{-1}\\ 7 = \sqrt{49}$

The square root of 49 equals 7, but the square root of -1 is an imaginary number.

The correct choice is <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>

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Dima020 [189]

Answer:

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Step-by-step explanation:

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3 years ago

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Marina86 [1]

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brilliants [131]

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