Can someone help me this is really confusing????? What is the solution set for the open sentence with the given replacement set?
1 answer:
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Inequalities are used to show the relationship between unequal expressions
- <em>The set notation of (5) and (6) are: </em>
<em> and </em>
<em>.</em>
- <em>See attachmen</em>t for the graphs
The following should be notated when plotting the graph of an inequality
- < and > are represented with open circles, while
and
are represented with closed circles
- The arrows of
and
point to the left, while the arrows of
and
So, we have:
Rewrite as:
The graph of will point to the right, and it will use an open circle
Split the inequality:
and
<em>It is not possible for -6 to be less than x and at the same time, x is greater than or equal to -2.</em>
<em />
Hence. cannot be represented on a graph
Split the inequality:
and
means that -4 is less than x or x is greater than -4.
So, we have:
and
If and
, then we make use of
because it contains more values of x.
The graph of will point to the right, and it will use an open circle
Read more about inequalities at:
Check the picture below.
keeping in mind that the point of tangency for a radius line and a tangent is alway a right-angle, since the "red" chord is parallel to the "green" tangent line outside, then the chord is cutting the "green" radius there in two equal halves at a right-angle, as you see in the picture.
we know the chord is 10 units long, so 5 + 5, since is perpendicularity with the radius will also cut the chord in two equal halves.
anyhow, all that said, we end up with triangle you see on the right-hand-side, and then we can just use the pythagorean theorem.
keeping in mind that the point of tangency for a radius line and a tangent is alway a right-angle, since the "red" chord is parallel to the "green" tangent line outside, then the chord is cutting the "green" radius there in two equal halves at a right-angle, as you see in the picture.
we know the chord is 10 units long, so 5 + 5, since is perpendicularity with the radius will also cut the chord in two equal halves.
anyhow, all that said, we end up with triangle you see on the right-hand-side, and then we can just use the pythagorean theorem.