-6(2/3), square root of 36, 6.4, 71/11
Answer:
f(x) = x^4/12 + 8x + 4
Step-by-step explanation:
f"(x) = x^2
Integrate both sides with respect to x
f'(x) = ∫ x^2 dx
= (x^2+1)/2+1
= (x^3)/3 + C
f(0) = 8
Put X = 0
f'(0) = 0+ C
8 = 0 + C
C= 8
f'(x) = x^3/3 + 8
Integrate f(x) again with respect to x
f(x) = ∫ (x^3 / 3 ) +8 dx
= ∫ x^3 / 3 dx + ∫8dx
= x^(3+1) / 3(3+1) + 8x + D
= x^4/12 + 8x + D
f(0) = 4
Put X = 0
f(0) = 0 + 0 + D
4 = D
Therefore
f(x) = x^4 /12 + 8x + 4
Answer:
The second answer is in standard form of equation
Substitute 51/5x into
Substitute that into
Hope this helps. Answer should be correct. Unless your quadratic equation is wrongly stated.
Answer:
20 and 50
Step-by-step explanation:
x + y = 70
y = 2x + 10
Use the substitution method:
y = 70 - x
y = 2x + 10
70 - x = 2x + 10
3x = 60
x = 20
x + y = 70
20 + y = 70
y = 50
<u>x = 20</u>
<u>y = 50</u>
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