What is the equation with a slope of 0 that has a point of (6,-11)?

1 answer:

5 0

$\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{-11})~\hspace{10em} \stackrel{slope}{m}\implies 0 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-11)}=\stackrel{m}{0}(x-\stackrel{x_1}{6}) \\\\\\ y+11=0\implies y=-11$

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