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Sav [38]
3 years ago
15

What is the equation with a slope of 0 that has a point of (6,-11)?

Mathematics
1 answer:
lianna [129]3 years ago
5 0

\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{-11})~\hspace{10em} \stackrel{slope}{m}\implies 0 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-11)}=\stackrel{m}{0}(x-\stackrel{x_1}{6}) \\\\\\ y+11=0\implies y=-11

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Solve the equation 2/5x - 1 = 9. Complete the solution and check your solution.
sukhopar [10]
2/5x - 1 = 9
+1 +1
10
—— ——
2/5 2/5

x = 50
6 0
3 years ago
Can anyone help with expanding this?
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Answer:

is this collage mathz

Step-by-step explanation:

7 0
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8 0
2 years ago
A small plane flew 808 miles in 4 hours with the wind. Then on the return trip flying against the wind it travels only 488 miles
Blababa [14]

Answer:

Step-by-step explanation:

let wind velocity=x

speed of plane=y

(x+y)*4=808

x+y=808/4=202   ...(1)

(y-x)*4=488

y-x=122 ...(2)

add (1) and (2)

2y=202+122=324

y=324/2=162

from (1)

x+162=202

x=202-162=40

wind velocity=40 m/hr

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8 0
2 years ago
Show all work please will give brainliest answer❕❗️❕❗️❕❗️❕❗️❕David drops a ball from a bridge at an initial height of 100 meters
Inessa [10]
First, 9.8 (Gravity) times 3 (time) equals 29.4, which is the velocity after 3 seconds. The kinematic equation for change in position that uses the variables we have is:
delta x= (v)(t) -0.5(acceleration)(time)^2
delta x= 29.4 times (3) - 0.5 (9.8) times 9
delta x= 44.1
100 minus 44.1 equals 55.9, which is the answer for part a.

Tell me if you need any clarification

PART B:
The kinematic equation for this is:
delta x= (initial velocity) times time plus 0.5 (a)(time)^2
100=(0)times(x) plus 0.5 (a)(time)^2
100=0.5(9.8)(x)^2
100=4.9x^2
100/4.9 is approxamitely 20.4.
The squareroot of this is approxamitely 4.5.
4.5 seconds

Tell me if you need any clarification
3 0
3 years ago
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