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enyata [817]
2 years ago
11

HURRY I HAVE 2 MINUTES

Mathematics
1 answer:
Black_prince [1.1K]2 years ago
5 0

Answer:

50

Step-by-step explanation:

................

..............

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Find a third degree polynomial function with real coefficients and with zeros 4 and 3+i
Anvisha [2.4K]
X = 4 ; x = 3 + i ; x = 3 - i

(If you get a zero that is adding or subtracting, you always need to write it twice but change the sign do they cancel out)

f(x) = (x-4)(x-3-i)(x-3+i)

Distributing the last two parenthesis first is always the best way to start off

(x-3-i)(x-3+i) has (x-3) in common so it can be separated to

(x-3)^2 + (-i)(+i)

(x^2 - 6x + 9) ; (-i)(+i) is always +1
(x^2 - 6x + 9) + 1
(x^2 - 6x + 10)

Now multiply this with (x-4)
x^3 - 6x^2 + 10x
- 4x^2 + 24x - 40

x^3 - 10x^2 + 34x - 40 = f(x)

3 0
3 years ago
9x−4y=−7 7x−12y=39 ​
Nina [5.8K]

what is  the question?

8 0
3 years ago
Write an equation of the line that passes through (5, −1) and is perpendicular to the line y=12x−1.
Lisa [10]

Step-by-step explanation:

solution

let,A(5,-1)

given

y=12x-1

or, y = 12 × x + (-1)

comparing it with y=mx+c

we get

x=1

y = c = -1

now

A(5,-1) and B(1,-1)

equation of line is,

(y-y1)/(x-x1) = (y2-y1)/(x2-x1)

or, (y+1)/(x-5) = (-1+1)/(1-5)

or, (y+1)/(x-5) = 0/-4

cross multiply

-4y-4 = 0

or, 0=4y+4

or, 4y+4=0 is the required eqn

I think this is the process and answer too.

I hope this helps you

4 0
3 years ago
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