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algol [13]
3 years ago
7

A number is doubled and then 1 is added to it. The answer is divided by 5 and then increased by 16. The final result is 18.

Mathematics
1 answer:
ipn [44]3 years ago
8 0
<h2>A.</h2>

So let's break down this sentence (Let n = unknown number):

  • "A number is doubled and then 1 is added to it"; Remember that double means multiplied by 2. With this sentence, we can determine that "2n + 1" is a part of the equation.
  • "The answer is divided by 5, and then increased by 16"; The "answer" they refer to is "2n + 1" from the prior sentence. Since this is divided by 5 and <em>then</em> added by 16, we can determine that \frac{2n+1}{5}+16 is a part of our equation.
  • "The final result is 18"; This means that the prior part of the equation is equal (=) to 18. <u>With this info, our full equation is \frac{2n+1}{5}+16=18</u>
<h2>B.</h2>

Now, let's solve our prior equation found in A. To solve for the unknown number, n, we need to isolate the variable onto 1 side of the equation. Firstly subtract both sides by 16 to cancel out the + 16 on the left side:

\frac{2n+1}{5}=2

Next, multiply both sides by 5 to cancel out the division on the left side:

2n+1=10

Next, subtract both sides by 1 to cancel out the + 1:

2n=9

Lastly, divide both sides by 2 to cancel out the multiplication:

n=\frac{9}{2}\ \textsf{OR}\ 4.5

<u>In short, the number is 9/2 or 4.5.</u>

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AP CALC 98 POINTS!!!!!!
bekas [8.4K]

Looking at this question again, I don't understand why you're told "for y=11". That doesn't seem relevant at all... So you can disregard the answer I posted a few minutes ago on your other question.

a) With x^2=-2+y+5\cos y, differentiate both sides with respect to x to get

2x=\dfrac{\mathrm dy}{\mathrm dx}-5\sin y\dfrac{\mathrm dy}{\mathrm dx}

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x}{1-5\sin y}

b) The point P occurs at x=2, which corresponds to a y-coordinate of

4=-2+y+5\cos y\implies y\approx4.928

The slope of the line tangent to this point is approximately

\dfrac{\mathrm dy}{\mathrm dx}\approx\dfrac{2(2)}{1-5\sin(4.928)}\approx0.68

so the equation of the tangent line is approximately

y-4.928=0.68(x-2)\implies y=0.68x+3.57

c) The tangent line to the graphed curve is vertical when \dfrac{\mathrm dy}{\mathrm dx} is undefined. This happens when 1-5\sin y=0, or y=\pi-\sin^{-1}\dfrac15+2n\pi and y=\sin^{-1}\dfrac15+2n\pi where n is any integer.

In case you're not sure where the general solution came from: We have

\sin y=\dfrac15

which has an infinite number of solutions. \sin^{-1}\dfrac15 is one of them, which we obtain by taking the inverse sine of both sides of this equation. Since \sin(\pi-x)=\sin x, we also know that \pi-\sin^{-1}\dfrac15 is a solution. And since \sin(x+2n\pi)=\sin x for integers n, we also know that we can add any multiple of 2\pi to these two solutions to get infinitely more solutions.

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3 years ago
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