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Korvikt [17]
3 years ago
12

What is a polynomial function in standard form with zeroes 1, 2, –3, and –3?

Mathematics
2 answers:
Darina [25.2K]3 years ago
7 0
Hello,

(x-1)(x-2)(x+3)²=(x²-3x+2)(x²+6x+9)
=x^4+3x^3-7x²-15x+18

Answer A
alexira [117]3 years ago
4 0
The zeroes are 1, 2, -3 and -3

we can make the zeroes into factors of 
(x-1), (x-2), (x+3)  and (x-3)

Multiply all the factors in order to get the polynomial function

g(x) = (x-1)(x-2)(x+3)(x-3)
g(x) <span>= x4 + 3x3 –7x2 – 15x + 18

So the correct answer is letter </span>A. g(x) = x4 + 3x3 –7x2 – 15x + 18
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The sum of the digits of a two-digit number is 8. If the digits are interchanged ,new number is 10 more than double the original
vova2212 [387]

Answer:

Original number 26.

Step-by-step explanation:

xy - two-digit number

1) x + y = 8

2) Original two-digit number can be written as

10*x + y

3) If the digits interchanged yx,

then the new number can be written as

10*y + x

4)  Double the original number is

2*(10*x + y)

5) New number is 10 more than double the original number

(10*y + x) - (2*(10*x + y)) = 10

6) Now we have the system of 2 equations:

x + y = 8

(10*y + x) - (2*(10*x + y)) = 10 -----> 10y + x - (20x + 2y) = 10 ---> 8y - 19x = 10

x = 8 - y

8y - 19(8 - y) = 10

8y - 152 +19y = 10

27y = 162

y = 6

x = 8 - y = 8 - 6 = 2

x = 2

So, x =2, y = 6.

Original number 26.

Check:

Original number 26.

New number 62.

Double of the original number = 2*26= 52.

New number is 10 more than double the original number :

62 - 52 = 10 True

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