we can divide the equation on (x+1) and if we have a real solutons (x+1) is a factor
is a factor because the remainder is 0
so the new form of the equation is
Please answer using the information provided (30 points for brainlyest)
1 answer:
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Let 
be the identity matrix. Then pick whatever matrix you like for 
.
Answer:
(0, 1 ) and (,
)
Step-by-step explanation:
Given the 2 equations
x³ - xy = 0 → (1)
x + y = 1 → (2) ( subtract x from both sides )
y = 1 - x → (3)
Substitute y = 1 - x into (1)
x² - x(1 - x) = 0
x² - x + x² = 0
2x² - x = 0 ← factor out x from each term on the left side
x(2x - 1) = 0
Equate each factor to zero and solve for x
x = 0
2x - 1 = 0 ⇒ 2x = 1 ⇒ x =
Substitute these values into (3) for corresponding values of y
x = 0 : y = 1 - 0 = 1 ⇒ (0, 1 )
x = : y = 1 -
=
⇒ (
,
)