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Flauer [41]
3 years ago
12

I need someone help please !!

Mathematics
1 answer:
Masteriza [31]3 years ago
5 0

It is asking for the tangent ratio at B.

In my answer; angle=theta

tan(theta)=opposite/adjacent

tan(theta)= 3/2

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Let p = log10 x, q = log10 y, and r = log10 z. (The 10s are base numbers.)
KatRina [158]

Answer:

(p / q^2 √r)

Just make x, y, z into p, q, r.

Very simple!

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3 years ago
{29, 29, 29, 28, 28, 27}
Tatiana [17]
A is the answer hope this helps
4 0
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What are prime factors of 1000?
Ede4ka [16]

Answer:

1,2,4,5,8,10,20,25,40,50,10,125,200,250,500,1000

Step-by-step explanation:

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1000=2*2*2*5*5*5

4 0
2 years ago
Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2). What is the area of the triangle? a 18 square units b 9 square unit
natka813 [3]

Answer:

Option C. 6 square units

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.  

Let  

a,b,c be the lengths of the sides of a triangle.  

The area is given by:

A=\sqrt{p(p-a)(p-b)(p-c)}

where

p is half the perimeter

p=\frac{a+b+c}{2}

we have

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

d=\sqrt{(-3-1)^{2}+(-2+2)^{2}}

d=\sqrt{(-4)^{2}+(0)^{2}}

dAB=4\ units

step 2

Find the distance BC

d=\sqrt{(-2+3)^{2}+(1+2)^{2}}

d=\sqrt{(1)^{2}+(3)^{2}}

dBC=\sqrt{10}\ units

step 3

Find the distance AC

d=\sqrt{(-2-1)^{2}+(1+2)^{2}}

d=\sqrt{(-3)^{2}+(3)^{2}}

dBC=\sqrt{18}\ units

step 4

a=AB=4\ units

b=BC=\sqrt{10}\ units

c=AC=\sqrt{18}\ units

Find the half perimeter p

p=\frac{4+\sqrt{10}+\sqrt{18}}{2}=5.70\ units

Find the area

A=\sqrt{5.7(5.7-4)(5.7-3.16)(5.7-4.24)}

A=\sqrt{5.7(1.7)(2.54)(1.46)}

A=\sqrt{35.93}

A=6\ units^{2}

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3 years ago
I need help with 1-32 it’s a test help ASAP thanks
Illusion [34]
What’s in it for me will u give me vbucks
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