I am assuming that we have to round the numbers to the nearest tens.
When rounding off numbers, if the number is more than half, then you round it up for example, if the number is 15 and you want to round it off, you round it up to 20. But if the number is 14 you round is down to 10
Therefore, 33 would be rounded off to 30 as 3 is less than 5 in the ones place if you get what I mean.
As for 89, you would round it up to 90 as the 9 in the ones place is more than 5.
Therefore the sum of 90 and 10 is 100.
Hope this helps!
The Slope of "<span>2x - 3y - 5 = 0" is:
m = 2/3.
Use the mx+y formula to solve this question.
The correct answer is: B
This is a verified answer. </span>
F. 24, this is because if you split the bigger square in half you’ll get 6 and perimeter is the addition of all sides. So 6+6+6+6=24
The most appropriate choice for simple interest will be given by- Balance of Jose after 1 year is $1050
What is simple interest?
Simple interest is the interest applied on the principal value after charging some certain percentage of rate for some certain amount of time.
If the principal value is p, rate is r % per annum and time is t years
Simple interest is calculated as
SI = p ₓ r ₓ t / 100
Here,
Principal for Jose = $1000
Rate = 5%
Time = 1 year
Simple interest = 1000x5x1/100
= $50
Amount = $(1000+50)
= $1050
Balance of Jose after 1 year is $1050
To learn more about simple interest, refer to the link:
brainly.com/question/25793394
#SPJ10
Answer:
Step-by-step explanation:
Given Annabella time for a race is 24.2 seconds, if another runnee's time was 6.43 seconds faster, then the time taken for another runnee's time will be 24.2 - 6.43 = 17.77secs.
Let a variable X be the difference between annabelle's time and the other runners time.
X = annabelle's time - other runners time.
X = 24.2 - (24.2 - 6.43)
X = 24.2-24.2+6.43
X = 6.43seconds
Hence the expression between annabelle's time and the other runners time is X = 24.2 - (24.2 - 6.43)
<em>The difference between annabelle's time and the other runners time is 6.43seconds</em>
