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Mademuasel [1]
4 years ago
9

A shipment of marbles with a mean diameter of 27 mm and a standard deviation of 0.15 mm is normally distributed. By how many sta

ndard deviations does a marble with a diameter of 26.85 mm differ from the mean?
0
0.15
1
2
Mathematics
2 answers:
mrs_skeptik [129]4 years ago
7 0

Answer:

A marble of 26.85mm in diameter is 1 standard deviation from the mean.

Step-by-step explanation:

For an approximately normal distributed random variable, the transformation Z = (X-media) / sd provides the distances from each value of the variable X to the mean measured in standard deviation units. Therefore, if mean = 27mm, sd = 0.15mm, for a marble of 26.85mm in diameter, you have:

Z = (26.85 - 27) / 0.15 = -1.0.

A marble with 26.85mm in diameter is 1 standard deviation from the mean.

Andrew [12]4 years ago
4 0
The answer is 1. there is 1 set of .15mm that separates 27 from 26.85.
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Explanation:

4x + y = 16 
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2x = 18
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Plug x = 9 into  2x + y = -2

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4 years ago
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3 years ago
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Step-by-step explanation:

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Answer:

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3 0
3 years ago
1) -2q-5= -11 2)3(8+k) = 33 3)4/6=x/9 4)6(y+3)=24 5)4k+8=26 6)8y=6+2y 7)3x-7=20 pls help!!!!!!!!!
KATRIN_1 [288]

Answer:

1) -2q-5= -11

-2q = -11+5

q = -6/-2 =3

2) 3(8+k) = 33

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3k = 33-24

K = 9/3 = 3

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3 0
3 years ago
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