The weight of the third heaviest among the four dogs is 2 kg.
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
The 4 dogs weight is 60 kg with each dog weight been different. The second heaviest dog weighs 28 kg.
Let the heaviest dog be 29 kg, the third heaviest be 2 kg and the fourth be 1 kg.
29 + 28 + 2 + 1 = 60 kg
The weight of the third heaviest among the four dogs is 2 kg.
Find out more on equation at: brainly.com/question/2972832
Solution
write the division as a fraction = 12y^4-4y^3 - 6y^2 + 36y - 22 over y-3 multiplied by r over y-3
r ×(2y^4 - 4y^3- 16y^2 + 36y- 22) over (y-3)^2
2ry^4 - 4ry^3 - 16ry^2 + 36ry - 22r over (y-3)^2
Answer:y intersept =-2
X interesept=2/5
Step-by-step explanation: let y=0
0=5x-2
2=5x
X=2/5
Let x=0
Y=-2
Answer:
arturo earned the ,most
Step-by-step explanation:
