Answer:
Step-by-step explanation:
(cos7A + cos3A - cos5A - cosA)÷(sin7A - sin3A - sin5a + sinA)
By using transformations,
[(cos7A - cos5A) + (cos3A - cosA)]÷[(sin7A - sin5A) - (sin3A - sinA)]....
we get...
=[(2sin6A.sinA)+(2sin2A.sinA)]÷[(2cos6A.sinA)-(2cos2A.sinA)]...
=[{2sinA(sin6A+sin2A)}]÷[{2sinA(cos6A-cos2A)]
=[{2sin4A.cos2A}÷{2sin4A.sin2A}]
=[(cos2A)÷(sin2A)]
=cot2A
Answer 32 pets.
Explanation: 64 divided by 2
Answer:
Devon
Step-by-step explanation:
lets use t=1 to compare
1. -5(12t+9)
if t = 1, -5(12+9) = -5(21) = negative number
2. 2(-6t-8)
if t = 1, 2(-6-8) = 2(-14) = negative number
3. -6(-2t+18)
if t = 1, -6(-2+18) = -6(16) = negative number
4. (-4(-3t-2)
if t = 1, -4(-3-2) = -4(-5) = 20 positive number
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