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murzikaleks [220]
3 years ago
14

The function g(x) = –x^2 + 16x – 44 written in vertex form is g(x) = –(x – 8)^2 + 20. Which is one of the transformations applie

d to the graph of f(x) = x^2 to change it into the graph of g(x) = –x^2 + 16x – 44?
a.The graph of f(x)= x^2 is widened
b.The graph of f(x)=x^2 is shifted left 8 units
c.The graph of f(x)=x^2 is shifted down 44 units
d.The graph of f(x)=x^2 is reflected over the x-axis
d.The graph of f(x)=x^2
Mathematics
1 answer:
Alexxandr [17]3 years ago
6 0
<span>a.The graph of f(x)= x^2 is widened</span>
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Answer:

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Step-by-step explanation:

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Answer:

\frac{1}{2\sqrt{5} }

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Let, \text{sin}^{-1}(\frac{x}{6}) = y

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Therefore, from equation (1),

\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

Or \frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

At x = 4,

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\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}

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                   =\frac{1}{6\sqrt{\frac{20}{36} }}

                   =\frac{1}{\sqrt{20}}

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