The mean of these workers is total salary/number of workers=(5*25000+3*27000+1*34000)/(5+3+1)=26667, approximately. The standard deviation formula is \sqrt(1/n*sum of (x_i-mu)^2) from 1 to n. Plug in n=9, mu=26667, the standard deviation is 2915 dollars approximately.
Answer:
7) 3m + 21
8) 8t + 12
9) 45 + 30r
10) 32n - 16n or just 16n
Step-by-step explanation:
just use the distributive property
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