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Xelga [282]
3 years ago
9

Find the surface area and volume of each solid to the nearest tenth. 16 m 15 m 17 m

Mathematics
1 answer:
Vikki [24]3 years ago
6 0
15 the answer is 15!!!!!
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Name a three-dimensional shape that has four triangular faces and one rectangular face. Name a three-dimensional shaoe that has
rodikova [14]

The answers would be pyramid and triangular prism.

3 0
3 years ago
The area of polygon MNOPQR = Area of a rectangle that is 9 square units + Area of a rectangle that is ___ square units. (Input w
vekshin1
You have the polygon MNOPQR which can be expressed as two rectangles pasted one next to each other.

To see the two rectangles in the picture, you can draw a line parallel to segment MR througn point N.

From the original picture you can state the dimensions of both rectangles.

Call S, the point where the line that you drew intercepts the segment RQ.

Then one rectangle is MNSR and the other rectangle is OPQS.

The measures of the sides of the rectangle MNSR are:

- the length of MN = length of SR = base

- the length of MR = the length of NS.= height

So its area is base * height, which you can all A1.

The measured of the rectangle OPQS are:

- segment OP = segment SQ = segment QR - segment SR = base

- segment PQ = segment OS = height

So its area is base * height, which you can call A2.

Then the area of the polygon MNOPQRS is A1 + A2. One of them is 9 u^2 and the other is what the answer is asking for, and that you have calculated above.

With this procedure you can tell the value needed.   

 
8 0
3 years ago
If i have 100 gummy vitamins and i take two a day how many months would they last me?
never [62]
100 vitamins/2 a day=50 days 50 days/30 days in a month (assumedly)= 5/3 months 1.66
4 0
3 years ago
Tell weather the given value is a solution of the inequality
natta225 [31]
Yes, 8 is a solution

r - 3 ≤ 9; r  = 8

plug in 8 to r

(8) - 3 ≤ 9
5 ≤ 9 (true)

hope this helps
4 0
3 years ago
Read 2 more answers
After the 4th half life how much of the sample is left if the mass is 100g.
vazorg [7]

Answer:

\huge\boxed{\sf 6.25 \ g}

Step-by-step explanation:

After every Half life , Half of the mass is left.

After 1st Half life = 100 g / 2 = 50 g

After 2nd Half life = 50 / 2 = 25 g

After 3rd Half life = 25 / 2 = 12.5 g

After 4th Half life = 12.5 / 2 = 6.25 g

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
6 0
2 years ago
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