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vagabundo [1.1K]
3 years ago
7

Give an example of an odd function and explain algebraically why it is odd. (3 points)

Mathematics
2 answers:
MrRissso [65]3 years ago
4 0

Answer: f(x)=5x^{3}-x


Step-by-step explanation:

1. By definition, algebraically, a function is odd when:

-f(x)=f(-x)

2. Therefore, if you have the following function:

f(x)=5x^{3}-x

You can know if it is odd by substituting x=-x:

f(-x)=5(-x)^{3}-(-x)

 f(-x)=-5x^{3}+x

3. -f(x) is:

-f(x)=-5x^{3}+x

4. Then, as -f(x)=f(-x) it is odd


klio [65]3 years ago
3 0

Answer:

See below

Step-by-step explanation:

In an odd function f(-x) will equal -f(x).

An example is f(x) = x^3:-

f(-x) = (-x)^3 and -f(x)  = -x^3:-

(-x)^3 = -x * -x * -x = -x^3.



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Answer:

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Solution,

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Total Money earned by Julie is equal to sum of number of wrapping paper multiplied with cost of wrapping paper and number of holiday paper multiplied with cost of holiday paper.

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13x+8y=292\ \ \ \ \ equation\ 1

Now, Mark sold 7 rolls of plain wrapping paper and 2 rolls of holiday paper and earns $118.

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(28x+8y)-(13x+8y)= 472-292\\\\28x+8y-13x-8y= 180\\\\15x=180\\\\x=\frac{180}{2} = \$12

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Hence Cost of one roll of plain wrapping paper is $12 and Cost of one roll of holiday paper is $17.

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