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Alexxx [7]
4 years ago
15

How do you recognize when an equation has like terms

Mathematics
1 answer:
galina1969 [7]4 years ago
7 0
Like terms" refers to individual terms that have the same variable in them. Also, the variable in any "like terms" is raised to the same power. For example: 3x and 10x are like terms (both have the variable x, raised to the 1st power). 14a2 and ba2 are also like terms (both have the variable a, raised to the 2nd power)
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John and Andrew have £3.40 between them. John has £1.20 more than Andrew. John has £u and Andrew £v
Dahasolnce [82]
In the given question, there are several information's of immense importance and they can be used to find the necessary answers. It is already given that John and Andrew have 3.40 pound together. It is also given that John has 1.20 pound more than Andrew. It is also assumed that John has"u" pound and Andrew has "v" pounds.
Then we can write the two equations as
u + v = 3.40
u = v + 1.20
To find the values of u and v, we can replace the u in the first equation with the value of u in the second equation. Then
u + v = 3.40
(v + 1.20) + v = 3.40
2v + 1.20 = 3.40
2v = 3.40 - 1.20
2v = 2.2
v = 2.2/2
  = 1.1
Now we replace the value of v in the first equation to find the value of u.
 u + v = 3.40
u + 1.1 = 3.40
u = 3.40 - 1.1
u = 2.3
6 0
3 years ago
Ruth buys 19 identical tickets for £280.25.<br> Estimate the cost of one ticket.
xxTIMURxx [149]

Answer:

The cost of one ticket is $14.75

Step-by-step explanation:

To find the cost of one ticket we need to divide 280.25 by 19

=$14.75

plz mark me as brainliest

3 0
3 years ago
Read 2 more answers
HEY YA'LL 30 PTS FOR 1 PROBLEM!<br> Given: m∠EYL=1/3 the measure of arc EHL<br> Find: m∠EYL.
GarryVolchara [31]

Answer:

45

Step-by-step explanation:

Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.

m<EYL = (1/2)(m(arc)EVL - m(arc)EHL)      Eq. 1

The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.

m(arc)EVL + m(arc)EHL = 360

m(arc)EVL = 360 - m(arc)EHL      Eq. 2

We are given this:

m<EYL = (1/3)m(arc)EHL       Eq. 3

Substitute equations 2 and 3 into equation 1.

(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]

Now we have a single unknown, m(arc)EHL, so we solve for it.

2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]

2m(arc)EHL = 1080 - 6m(arc)EHL

8m(arc)EHL = 1080

m(arc)EHL = 135

Substitute the arc measure just found in Equation 3.

m<EYL = (1/3)m(arc)EHL

m<EYL = (1/3)(135)

m<EYL = 45

5 0
3 years ago
You purchase pair of pants for $34.60 and a shirt for $12.30. If you need to pay 8% sales tax, what is the final price?
pantera1 [17]

Answer:

34.60+12.30=46.90

46.90/100=0.469

0.469*8=$3.75

7 0
4 years ago
If (62)x = 1 what is the value of x? Explain your answer.
Alex
Whenever you solve an equation with a single variable you need to isolate the variable by itself on one side of the equal sign.  Just be sure that whatever operations you perform on one side you perform on the other sides as well.

62x=1  divide both sides by 62

x=1/62
3 0
4 years ago
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