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2 years ago

I know y'all brainly People Smart so maybe you could solve my whole homework for me thank you

Mathematics

1 answer:

Ostrovityanka [42]2 years ago

7 0

6 cups?? Maybe I’m not 100% sure

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What is the value of y when the value of x is 1

Rudiy27

60 because every x number equals 60 y numbers also if you divide the last x number which is 4 by the last y number that is 240 you get 60

5 0

3 years ago

Find principal of a loan at 11% for 5 years with $426.25 simple interest

Ahat [919]

Answer:

$P=775$

Step-by-step explanation:

The Simple Interest Equation is $A = P(1 + rt)$

where

A = Total Accrued Amount (principal + interest)

P = Principal Amount

I = Interest Amount

t = Time Period involved in months or years

In this case, we do not know the values of the equation (A and P), but we know the amount of interest accrued

If we define our principal whit this formula, we are able to know the rest of the values:

$A-P= interest$

clearing

$A=interest+P$

replacing

$426.25 + P = P (1+(0.11(5))$

Solving

$426.25+P=1.55P$

$P-1.55P=-426.25$

$-0.55P=-426.65$

$P=\frac{-426.25}{-0.55}$

$P=775$

7 0

2 years ago

Un submarino puede descender a una velocidad de –2,5 metros / segundo. Supongamos que el submarino comienza a una profundidad de

Mariulka [41]

17.5

Step-by-step explanation:

3 0

3 years ago

Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How

Scorpion4ik [409]

let's check how much is it after 2 years firstly.

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275$

Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}$

$\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}$

4 0

3 years ago

I am really bad at math. What is AC?

kotykmax [81]

The line from a to c

4 0

3 years ago

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I know y'all brainly People Smart so maybe you could solve my whole homework for me thank you ​

I know y'all brainly People Smart so maybe you could solve my whole homework for me thank you