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lapo4ka [179]
2 years ago
13

The following chips are placed in a bucket: 1 red, 9 yellow, 6 blue, and 11 green. One chip is randomly selected from the bucket

.
What is the probability that the chip is either yellow or green?
Mathematics
2 answers:
marin [14]2 years ago
5 0
Answer: 20/27

Step-by-Step Explanation:

Red Chips = 1
Yellow Chips = 9
Blue Chips = 6
Green Chips = 11
Total = 1 + 9 + 6 + 11 = 27

Probability (Yellow or Green) :-
=> (Yellow Chips + Green Chips)/Total
=> (9 + 11)/27
= 20/27

Probability (Yellow or Green) = 20/27
Oxana [17]2 years ago
3 0

Answer:

20 out of 27

Step-by-step explanation:

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3 years ago
What are all the possible 3 digit number combinations 0-9?
Arada [10]
That would be 10 x 10 x 10  = 1000
7 0
4 years ago
Students sold yogurt to raise money for graduation. The first 20 yogurts sold cost $5 each. To sell more yogurt they lowered the
goblinko [34]
5(20) + 4y = 216
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7 0
3 years ago
A locker combination consists of two nonzero digits, and each combination consists of different digits. Event A is defined as ch
Troyanec [42]

The correct answer is option B which is P ( A|B) will be ( 4 / 9 ).

<h3>What is probability?</h3>

Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

Given that:-

  • A locker combination consists of two nonzero digits, and each combination consists of different digits. Event A is defined as choosing an odd number as the first digit, and event B is defined as choosing an odd number as the second digit.

The total sample will have 9 numbers

S = { 1,2,3,4,5,6,7,8,9} = 9

Even Number = { 2,4,6,8} = 4

Odd Number  = { 1,3,5,7,9} = 5

P ( A ) = ( 4 / 9 )

P ( B ) = ( 5 / 9 )

The probability will be calculated as:-

P( A:B ) = \dfrac{P(A)\times P(B)}{P(B)}

P( A:B ) =\dfrac{( 5/9 ) ( 4/9 )}{5 / 9 }

P( A:B ) = 4 / 9

Therefore the correct answer is option B which is P ( A|B) will be ( 4 / 9 ).

To know more about probability follow

brainly.com/question/24756209

#SPJ1

4 0
2 years ago
PROVE THAT:<br><br>cos 20° - sin 20° = ​​ \sqrt{2}sin25°<br><br>​
Lemur [1.5K]

Answer:

See below.

Step-by-step explanation:

\cos(20)-\sin(20)=\sqrt{2}\sin(25)

First, use the co-function identity:

\sin(90-x)=\cos(x)

We can turn the second term into cosine:

\sin(20)=\sin(90-70)=\cos(70)

Substitute:

\cos(20)-\cos(70)=\sqrt{2}\sin(25)

Now, use the sum to product formulas. We will use the following:

\cos(x)-\cos(y)=-2\sin(\frac{x+y}{2})\sin(\frac{x-y}{2})

Substitute:

\cos(20)-\cos(70)=-2\sin(\frac{20+70}{2})\sin(\frac{20-70}{2})\\\cos(20)-\cos(70)  =-2\sin(45)\sin(-25)\\\cos(20)-\cos(70)=-2(\frac{\sqrt{2}}{2})\sin(-25)\\ \cos(20)-\cos(70)=-\sqrt{2}\sin(-25)

Use the even-odd identity:

\sin(-x)=-\sin(x)

Therefore:

\cos(20)-\cos(70)=-\sqrt{2}\sin(-25)\\\cos(20)-\cos(70)=-\sqrt{2}\cdot-\sin(25)\\\cos(20)-\cos(70)=\sqrt{2}\sin(25)

Replace the second term with the original term:

\cos(20)-\sin(20)=\sqrt{2}\sin(25)

Proof complete.

4 0
4 years ago
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