Ask question

Ask question

All categories

2 years ago

13

The following chips are placed in a bucket: 1 red, 9 yellow, 6 blue, and 11 green. One chip is randomly selected from the bucket

.
What is the probability that the chip is either yellow or green?

2 answers:

marin [14]2 years ago

5 0

Answer: 20/27

Step-by-Step Explanation:

Red Chips = 1
Yellow Chips = 9
Blue Chips = 6
Green Chips = 11
Total = 1 + 9 + 6 + 11 = 27

Probability (Yellow or Green) :-
=> (Yellow Chips + Green Chips)/Total
=> (9 + 11)/27
= 20/27

Probability (Yellow or Green) = 20/27

Oxana [17]2 years ago

3 0

Answer:

20 out of 27

Step-by-step explanation:

You might be interested in

A car traveling 118 miles uses 4 gallons of gas. At the rate, how many gallons will it use traveling 227 miles?

sashaice [31]

Answer:

b.7.69

Step-by-step explanation:

188/4=29.5

29.5 gal per mile

227/29.5=7.69

8 0

2 years ago

Question 6 of 10

Tanya [424]

Answer:

- 2

Step-by-step explanation:

Parallel lines have equal slopes

Then the slope of the red line is equal to the slope of the green line, that is

slope of red line = - 2

3 0

2 years ago

PLEASE HELP NEED THIS ANSWERED CORRECTLY

Helen [10]

f(3) = 1.9

Solution:

Given function:

$$f(x)=\frac{14}{7+2 e^{-0.6 x}}$

To find f(3):

Substitute x = 3 in the given function.

$$f(3)=\frac{14}{7+2 e^{-0.6 (3)}}$

$$f(3)=\frac{14}{7+2 e^{-1.8}}$

Let us first simplify $2e^{-1.8}$ .

Apply exponent rule: $a^{-b}=\frac{1}{a^{b}}$

$2e^{-1.8}=2\frac{1}{e^{1.8}}$

The value of $e^{1.8}=6.04964$ . (using calculator)

$$\frac{2}{e^{1.8}}=\frac{2}{6.04964}=0.33059$

$2e^{-1.8}=0.33059$

Substitute this value in f(3).

$$f(3)=\frac{14}{7+0.33059}$

$$f(3)=\frac{14}{7.33059}$

$$f(3)=1.90980$

f(3) = 1.9

Hence the value of f(3) is 1.9.

3 0

3 years ago

Which of the following words does not indicate addition?

dsp73

Th answer is c. quotient, because it has to do with multiplication and not addition.

6 0

3 years ago

Read 2 more answers

Suppose a lawn and garden company wants to determine the current percentage of customers who use fertilizer on their lawns. How

marishachu [46]

Answer:

n=601

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.04$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Since we don't have a prior estimation for the proportion we can use 0.5 as estimation. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.96})^2}=600.25$

And rounded up we have that n=601

3 0

3 years ago