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Ipatiy [6.2K]
3 years ago
15

BRAINLIESTTT ASAP! PLEASE HELP ME :)

Mathematics
2 answers:
drek231 [11]3 years ago
8 0

Answer:

Step-by-step explanation:

Just plug in 20 for t:

f(20)=\frac{60*20}{20^2+46}=\frac{1200}{400+46}=\frac{1200}{446}=2.69058

Llana [10]3 years ago
7 0

Answer:

\displaystyle 2\frac{154}{223}\:mg. = f(20)

Step-by-step explanation:

\displaystyle \frac{60[20]}{20^2 + 46} = \frac{1200}{400 + 46} = \frac{1200}{446} = 2\frac{154}{223}

I am joyous to assist you anytime.

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The region r is enclosed by the curves y=4-4x2 and y=0
Misha Larkins [42]

The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0 is 16/3 or 5.333 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0

The intersection points will be

       y₁ = y₂

4 - 4x² = 0

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Then the area bounded by the curves will be

\rm Area = \int _{-1}^1 (y_1-  y_2) dx\\\\Area = \int _{-1}^1 (4 - 4x^2) dx\\\\Area = \left [ 4x  - \dfrac{4x^3}{3} \right ]_{-1}^1\\\\Area = 4 \left ( 1 + 1 \right ) - \dfrac{4}{3} \left ( 1^3 - (-1)^3 \right )\\\\Area = 8 - \dfrac{8}{3}\\\\Area = \dfrac{16}{3} = 5.333 \

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

6 0
2 years ago
If the volume of a cube is 512 how much is the volume if its only 3/4 full
charle [14.2K]

Answer:

384

Step-by-step explanation:

You can find it by dividing 512 to 4 parts

512 divided by 4 = 128

Now multiply 128 by 3 because the cube is 3/4 full

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384 is your answer

7 0
3 years ago
In what step did he make an error?
Ilya [14]

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Answer:

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