Answer:
The signal would have experienced aliasing.
Step-by-step explanation:
Given that:
the bandwidth of the signal
= 36MHz
= 36 × 10⁶ Hz
The sampling frequency
= 36 × 10⁶ Hz
Suppose the sampling frequency is equivalent to the bandwidth of the signal, then aliasing will occur.
Therefore, according to the Nyquist criteria;
Nyquist criteria posit that if the sampling frequency is more above twice the maximum frequency to be sampled, a repeating waveform can be accurately reconstructed.
∴
By Nyquist criteria, for perfect reconstruction of an original signal, i.e. the received signal without aliasing effect;
Then,

∴
The signal would have experienced aliasing.
Answer:
.26
P(C) = .6*.3 + .4 *.2
= .18+.08
= .26
Step-by-step explanation:
1/12? Tell me if that’s right I’m not that good at it but I’m pretty sure it’s 1/12
I believe the answer would be X=7
It’s been a little bit
2.6 rounds to 3, and 0.33 would round to 0.50. Adding 3 and 0.50 together would equal to 3.50. 59 and 3.50 are no where near to each other which concludes Minh is incorrect.
(Please mark me brainliest)