Answer:
For this case, we have the following equation (according to the comments):
First, we factor the quadratic expression in the denominator:
Then, we multiply both sides of the equation by (a-2) (a + 2):
Later, canceling similar terms we have:
We do distributive property on the left side of the equation:
By grouping variables and constant terms we have:
Rewriting we have:
Finally, by clearing "a" we have:
Note: the value of a is a extraneous solution because it makes the denominator of the original equation equal to zero.
Answer:
the student correct, but the value of a= -2 is an extraneous solution
Numbers 3,4,5 make this inequality true
8+3=11
8+4=12
8+5=13
<span> x =(-12-√-432)/18=(-2-2i√<span> 3 </span>)/3= -0.6667-1.1547i</span><span> x =(-12+√-432)/18=(-2+2i√<span> 3 </span>)/3= -0.6667+1.1547i</span><span> x = 4/3 = 1.333</span>
Answer:
9/16
Step-by-step explanation:
2 1/4=2.25
2.25/4=0.5625
9/16=0.5625
I hope this is right and that this helps.
Answer:
He had 534.45 more in credits that debits
Step-by-step explanation:
Ignatius hd $534.45 more in credits than in debits. Since Ignatius had an initial balance of $124.82 at the beginning of the month and ended the month with $659.27 he was up money versus what he had in his account at the beginning of the month. During the month Ignatius made money that was credited to his account so that he ended it with a higher balance.