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Juliette [100K]
3 years ago
9

How do I solve this Y= -8x+56 2x+2y=56

Mathematics
1 answer:
Deffense [45]3 years ago
7 0
Y  = -8x + 56
2y= -2x + 56 (you want to get rid of one variable then solve for it then solve for                         the other)

-2(y=-8x+56)
2y=-2x+56

-2y=16x-112
2y=-2x+56     (see how multi the first equation by -2 gets the y's to cancel so                     can solve for x. Now sum up the equations)
0= 14x-56
x= 4

now plug x=4 into any original equation Y=-8x+56
Y = -8(4)+56
Y=24

hope this helps

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PLZ HELP OR I FAIL MY TEST
Volgvan

Answer:

time upstream=24/8=3 hours

time downstream=24/12=2 hours

Step-by-step explanation:

If R*T=D, and R is speed + or - current, how can you find the rate without the time, and how can you find the time without the rate?

THE KEY WAS WHEN WE WERE TOLD THAT IT TAKES ONE HOUR LONGER TO GO UPSTREAM THAN DOWNSTREAM BECAUSE T=D/R AND WE ARE TOLD THAT:

D/R(Upstream) minus 1 equals D/R (DOWNSTREAM)



Let x=rate of current

distance(d)=rate(r) times time(t) or d=rt or t=d/r

distance upstream=distance downstream=24 mi

rate upstream=10-x

rate downstream=10+x

time upstream=(distance upstream)/(rate upstream)=24/(10-x)

time downstream=(distance downstream)/(rate downstream)=24/(10+x)

Now, we are told that time upstream minus one hour equals time downstream. So our equation to solve is:

24/(10-x)-1=24/(10+x) Multiply both sides by (10-x)(10+x)

24(10+x)(10-x)/(10-x)-1(10-x)(10+x)=24(10-x)/(10+x)/(10+x) clear fractions


24(10+x)-(10-x)(10+x)=24(10-x) clear parens

240+24x-100-10x+10x+x^2=240-24x subtract 240 from and add 24x to both sides

240-240+24x+24x-100+x^2=240-240-24x+24x collect like terms

x^2+48x-100=0 ----------------quadratic equation in standard form

This equation can be factored:

(x+50)(x-2)=0

x=-50 mph----------------discount the negative value for speed

and

x=2 mph----------------------speed of the current

CK

10-x=10-2= 8 mph -----------------------speed upstream

10+x=10+2=12 mph--------------------------speed downstream

time upstream=24/8=3 hours

time downstream=24/12=2 hours

so 3-2=1----takes 1 hour longer upstream

7 0
3 years ago
Easy pllsssssss help
viktelen [127]

Answer:

87.5(the first one)

Step-by-step explanation:

first simplify 4 to the 5th power(20) and multiply by 4 to the -7th(-35) and you will get -700 divide that by 4 to the -2nd(-8) and you will get 87.5

6 0
3 years ago
Read 2 more answers
If an object is dropped from a height of 96ft, the function h(t) = -62 + 96 gives the height of the object after t seconds. When
Shalnov [3]

Answer:

Step-by-step explanation:Since we want to know how much time elapsed since the object was launched until it ht the ground. At the ground, the height is 0.

 

Therefore the equation  h(t) = 80t – 16t2 becomes 0= 80t – 16t2

 

Solving the equation for t gives  80t =16t2 or 16t=80 or t=5sec

 

The object hits the ground 5 seconds after it is launched.

7 0
3 years ago
A cone has a diameter of 4 cm and a height of 11 cm. What is the volume 1 point
anzhelika [568]

Answer: 46.05

Step-by-step explanation:

1/3 * 3.14 * 4 * 11 = 46.05 (rounded to the tenth)

4 0
3 years ago
Someone help me out please
uysha [10]

1 step (B): raise both sides of the equation to the power of 2.

(\sqrt{x+3}-\sqrt{2x-1})^2=(-2)^2,\\   (x+3)-2\sqrt{x+3}\cdot \sqrt{2x-1}+(2x-1)=4,\\ 3x+2-2\sqrt{x+3}\cdot \sqrt{2x-1}=4.

2 step (A): simplify to obtain the final radical term on one side of the equation.

-2\sqrt{x+3}\cdot \sqrt{2x-1}=4-3x-2,\\ -2\sqrt{x+3}\cdot \sqrt{2x-1}=2-3x,\\ 2\sqrt{x+3}\cdot \sqrt{2x-1}=3x-2.

3 step (F): raise both sides of the equation to the power of 2 again.

(2\sqrt{x+3}\cdot \sqrt{2x-1})^2=(3x-2)^2,\\ 4(x+3)(2x-1)=(3x-2)^2.

4 step (E): simplify to get a quadratic equation.

4(2x^2-x+6x-3)=(3x)^2-2\cdot 3x\cdot 2+2^2,\\ 8x^2+20x-12=9x^2-12x+4,\\ x^2-32x+16=0.

5 step (D): use the quadratic formula to find the values of x.

D=(-32)^2-4\cdot 16=1024-64=960, \\ \sqrt{D} =8\sqrt{5} ,\\ x_{1,2}=\dfrac{32\pm 8\sqrt{5}}{2} =16\pm 4\sqrt{5}.

6 step (C): apply the zero product rule.

x^2-32x+16=(x-16-4\sqrt{5}) (x-16+4\sqrt{5}) ,\\ (x-16-4\sqrt{5}) (x-16+4\sqrt{5}) =0,\\ x_1=16+4\sqrt{5} ,x_2=16-4\sqrt{5}.

Additional 7 step: check these solutions, substituting into the initial equation.

3 0
3 years ago
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