Please help, if u get it right i will give u brainliest

Mathematics

1 answer:

padilas [110]3 years ago

4 0

Answer:

2.27%

Step-by-step explanation:

Lets start by making the names letters, J C and A respectively.

The total is 44 dollars. J paid 34%, which would be 14.96. He pays a total of $15. C paid 50%, which is 22 dollars. A pays 17%, which would be 7.48. She pays a total of $8.

15 + 8 + 22 = $45, meaning they paid an extra 1 dollar. One dollar is 1/44th of $44, or 2.27%.

Note: 2.27% is 2.272727272727 repeated, do what you will with that information, every site is different.

You might be interested in

Negative symbol as opposite | HELP PLS

Pepsi [2]

Answer: I would have to say its zero

Sorry if I got it wrong

4 0

3 years ago

Read 2 more answers

9+10 ii am struggling really bad plz help.

Valentin [98]

Answer:

Step-by-step explanation:

9+10=19.

Replace the 0 in the ten with the 9.

3 0

3 years ago

A clinical trial was conducted to test the effectiveness of the drug zopiclone for treating insomnia in older subjects. Before t

aleksklad [387]

Answer:

We cannot say that the mean wake time are different before and after the treatment, with 98% certainty. So the zopiclone doesn't appear to be effective.

Step-by-step explanation:

The goal of this analysis is to determine if the mean wake time before the treatment is statistically significant. The question informed us the mean wake time before and after the treatment, the number of subjects and the standard deviation of the sample after treatment. So using the formula, we can calculate the confidence interval as following:

$IC[\mu ; 98\%] = \overline{y} \pm t_{0.99,n-1}\sqrt{\frac{Var(y)}{n}}$

Knowing that $t_{0.99,15} = 2.602$ :

$IC[\mu ; 98\%] = 98.9 \pm 2.602\frac{42.3}{4} \Rightarrow 98.9 \pm 27.516$

$IC[\mu ; 98\%] = [71.387 ; 126,416]$

Note that $102.8 \in [71.384 ; 126.416]$ so we cannot say, with 98% confidence, that the mean wake time before treatment is different than the mean wake time after treatment. So the zopiclone doesn't appear to be effective.