If it is 76 feet LOWER than 73 above sea level, then you must do
73-76= -3
So Mudville is 3 feet BELOW sea level.
Answer:
15% markup
Step-by-step explanation:
5% markup would be $1. Since 20*5% or 20*.05=1
We can multiply it by 3 to find the percent for $3 markup. Which is 15% or 0.15
Answer:
$496, 000
Step-by-step explanation:
2021 is 11 years since 2010, hence t = 11
Substitute t = 11 into the equation
p = (1.95 × 11²) + (12.25 × 11) + 125
= 235.95 + 134.75 + 125
= 495.7 ( thousands of dollars ), thus the best estimate is
p = $ 496, 000
Answer:
- After 4 seconds the height is 480 meters.
- The maximum height is 484 meters.
- The ball hits the ground after 10 seconds
Step-by-step explanation:
The height after four seconds is h(4) = -16 * r² + 144*4+160 = 480
The maximum height of the ball is the value it takes at its vertex 'v = -b/2a'. In this case a = -16 and b = 144, so the v = -144/-32 = 4.5. The maximum height of the ball as a result is h(4.5) = -16 (4.5)² + 144*4.5 + 160 = 484
To find the moment the ball hits the ground, we need to find when h takes the value 0 by using the quadratic formula, with a = -16, b = 144 and c = 160.
Since t cant take negative values, then the correct value is 10. The ball hits the ground after 10 seconds.
Answer:
w =< 70
(width is less or equal to 70 inches)
Step-by-step explanation:
Let l = length, w = width, h = height
Restrictions given in this question:
'sum of perimeter of the base and the height cannot exceed 130 inches'
perimeter of the base is 2 width and 2 length of the box
perimeter = 2w + 2l
Therefore, inequality involves here is
2w + 2l + h =< 130
(Note that =< here means less or equal)
Then a new condition given with
height, h = 60 in
and length is 2.5 times the width
l = 2.5w
Substitute this new condition into the equation will give us the following:
2w + 2(2.5w) + 60 =< 130
2w + 5w + 60 =< 130
7w + 60 =< 130
7w =< 130-60
7w =< 70
w =< 10
