Surface area is an important factor in limiting cell growth because
a. the cell can burst if the membrane becomes too large.
b. materials cannot enter the cell if the surface is too large.
c. the cell may become too large to take in enough food and to remove enough wastes.
d. waste products cannot leave the cell if the cell is too small.
Answer:
c. the cell may become too large to take in enough food and to remove enough wastes.
Explanation:
The exchange of substances with surroundings is done by cells by the process of diffusion. The rate of diffusion of substances requires the presence of a higher surface area than volume. As the cells become larger, their surface area is reduced with respect to the volume. Therefore, larger cells can not support the diffusion of substances in and out as required for its proper functioning. If cells are allowed to grow continuously, they will not be able to intake the requires materials such as food and to release the waste outside.
Note about the question:
Probably there are options for this question, but I failed in finding them. However, in the explanation box I will explain the reason for the lack of white flowers in the F1.
Answer:
The purple phenotype is dominant over the white phenotype. The allele that expresses the purple color is dominant and, in a heterozygous state, hides the expression of the recessive allele that expresses the white color. Principle of dominance.
Explanation:
Due to technical problems, you will find the complete explanation in the attached files.
Answer:
The answer would be A, to lead sperm cells to the ovary. Hope this helps you out!
?????? What's even the question?
Hey There Maiam,
<span>What is the symbol equation for aerobic respiration?
Answer: </span><span>1. </span>Aerobic Respiration<span>. It is important that you learn both the word and chemical </span>equation<span>. In the above </span>equations<span> we see that glucose is broken down by oxygen to release energy with carbon dioxide and water being produced as by-products of the reaction</span>
