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shutvik [7]
2 years ago
7

$6.50 is what percent of $130

Mathematics
1 answer:
melisa1 [442]2 years ago
6 0
   
\displaystyle  \\ 
p =  \frac{6.5}{130} \times 100 =  \frac{6.5\times 100}{130}= \frac{650}{130}= \boxed{ 5\% }



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In triangle MNO shown below, segment NP is an altitude:
Effectus [21]

Answer:  C. Definition of an Altitude

Step-by-step explanation:

Given: In triangle MNO shown below, segment NP is an altitude from the right angle.

Let ∠MNP=x

Then ∠PNO=90°-x

Therefore in triangle MNO,

∠MPN=∠NPO =90°  [by definition of Altitude]

[Definition of altitude : A line which passes through a vertex of a triangle, and joins the opposite side forming right angles. ]

Now using angle sum property in ΔMNP

∠MNP+∠MPN+∠PMN=180°

⇒x+90°+∠PMN=180°

⇒∠PMN=180°-90°-x

⇒∠PMN=90°-x

Now, in ΔMNO and ΔPNO

∠PMN=∠PNO=90°-x

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Therefore by AA similarity postulate, we have

ΔMNO ≈ ΔPNO

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2 years ago
Wats 80 times 80? please answer
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Step-by-step explanation:

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3 years ago
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Consider the following quadratic function Part 3 of 6: Find the x-intercepts. Express it in ordered pairs.Part 4 of 6: Find the
maksim [4K]

Answer:

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Given a quadratic function, we know that the graph is a parabola. The general form of a parabola is:

y=ax^2+bx+c

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y=-x^2-6x-13

Then:

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For this part, we need to find the x-intercepts. This is, when y = 0:

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To solve this, we can use the quadratic formula:

x_{1,2}=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot(-1)\cdot(-13)}}{2(-1)}

And solve:

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Since there is no solution to the square root of a negative number, the function does not have any x-intercept. The correct option is ZERO x-intercepts.

Part 4:

To find the y intercept, we need to find the value of y when x = 0:

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Part 5:

Now we need to find two points in the parabola. Let-s evaluate the function when x = 1 and x = -1:

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Part 6:

Now, we can use 3 points to find the graph of the parabola.

We can locate (1, -20) and (-1, -8)

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Then, y-coordinate of the vertex is:

y=-(-3)^2-6(-3)-13=-9+18-13=-4

The third point we can use is (-3, -4)

Now we can locate them in the cartesian plane:

And that's enough to get the full graph:

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