Well this is simple a calculator type problem...but if you are curious as the the algorithm used by simple calculators and such...
They use a Newtonian approximation until it surpasses the precision level of the calculator or computer program..
A newtonian approximation is an interative process that gets closer and closer to the actual answer to any mathematical problem...it is of the form:
x-(f(x)/(df/dx))
In a square root problem you wish to know:
x=√n where x is the root and n is the number
x^2=n
x^2-n=0
So f(x)=x^2-n and df/dx=2x so using the definition of the newton approximation you have:
x-((x^2-n)/(2x)) which simplifies further to:
(2x^2-x^2+n)/(2x)
(x^2+n)/(2x), where you can choose any starting value of x that you desire (though convergence to an exact (if possible) solution will be swifter the closer xi is to the actual value x)
In this case the number, n=95.54, so a decent starting value for x would be 10.
Using this initial x in (x^2+95.54)/(2x) will result in the following iterative sequence of x.
10, 9.777, 9.774457, 9.7744565, 9.7744565066299210578124802523397
The calculator result for my calc is: 9.7744565066299210578124802523381
So you see how accurate the newton method is in just a few iterations. :P
<span>So rather than think about how to find the whole numbers, let's try to find the two perfect squares nearest to 38. There is one greater than it and one smaller than it. The square root will lie between the squared value of each. (e.g. 64 is the perfect square, 8 is the squared value i refer to)
</span><span>
6 ,7. 6squared is 36 and 7 squared is 42
therefore 38 lies between these two numbers</span>
Answer:
The red shape
Step-by-step explanation:
This is because they are of the same shape and size.
They must look the same in size and shape type.
HOPE THIS HELPED
