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3 years ago

V=s^2+1/2sh solve for h

1 answer:

8 0

First, you separate the h variable by subtracting s^2 on both sides of the equation, getting
V - s^2 = sh/2
Then, all you have to do is divide both sides by s/2, so you get
h = 2*(v - s^2)/s as your final answer.

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Each morning librarians place 560 books on a book shelf in the school library. Each student that visits library that day takes e

Alex73 [517]

Answer:

Step-by-step explanation:

560=3s+b

560=3×150+b

b=560-450=110

when s=149,b=560-3×149=560-447=113

s=2,b=560-3×2=560-6=554

s=1,b=560-3×1=557

s=0,b=560-3×o=560

so domain of b={110,113,116,...,554,557,560}

7 0

3 years ago

How do I graph y=5/3x

babymother [125]

Just do the slope of 5/3×

6 0

3 years ago

Item 8 Solve for x. Use the quadratic formula. 2x2−5x−9=0 Enter the solutions, in simplified radical form, in the boxes.

Lubov Fominskaja [6]

Answer:

5+√97/4

Also 5-√97/4

Step-by-step explanation:

The Quadratic formula is x=-b+-√b^2-4ac/2a

This means that we should plug the values for A B AND C into the formula

We can work out that

A = 2

B=-5

C=-9

Once we have put these into the formula we get

5+√97/4 (all over 4) aka 3.71

Also 5-√97/4 (all over 4) aka -1.21

7 0

3 years ago

Read 2 more answers

You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us

Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that

step 1

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$r=10\%=10/100=0.10\\n=4$

substitute in the formula above

$A=P(1+\frac{0.10}{4})^{4t}$

$A=P(1.025)^{4t}$

Applying property of exponents

$A=P[(1.025)^{4}]^{t}$

$A=P(1.1038)^{t}$

step 2

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$r=10\%=10/100=0.10$

substitute in the formula above

$A=P(e)^{0.10t}$

Applying property of exponents

$A=P[(e)^{0.10}]^{t}$

$A=P(1.1052)^{t}$

step 3

Compare the final amount

$P(1.1052)^{t} > P(1.1038)^{t}$

therefore

Find the difference

$P(1.1052)^{t} - P(1.1038)^{t}$ ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.

3 0

3 years ago

Please answer, thank you

cupoosta [38]

Answer:

Step-by-step explanation:

Since y = -3 we can plug straight into the other equation

--> -x + 2y = -6

-x + 2(-3) = -6

-x - 6 = -6

-x = 0

x = 0

To graph this draw a horizontal like across the page at y = -3 and a vertical line down the page to represent x = 0

The point where these lines intersect is (0,-3)

So that would be the ordered pair solution.

4 0

3 years ago