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2 years ago

Simplify the Equation Below Pls answer :( 8x - 7 + 6x + 3

Mathematics

2 answers:

Angelina_Jolie [31]2 years ago

7 0

Answer:

14x-4

Step-by-step explanation:

Liono4ka [1.6K]2 years ago

5 0

Answer:

14x-4

Step-by-step explanation:

8x-7+6x+3

8x+6x-7+3

14x-7+3

14x-4

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HELP PLEASE points Savanah is shopping for planters for her new plants. Which measurement should she use to determine how much s

Nady [450]

Answer:

D. Volume

Explanation:

volume - amount of space that a substance occupies

Here the substance is soil and planter will hold the specific volume of soil.

5 0

2 years ago

Help this is due today

RoseWind [281]

Answer:

m = $\frac{-3}{4}$

Step-by-step explanation:

We are given two points ( -3, 1 ) and ( 1, -2).

The slope formula is m = $\frac{rise}{run}$ = $\frac{y2 - y1}{x2 - x1}$

So, we have $\frac{(-2)-(1)}{(1)-(-3)}$ = $\frac{-3}{1+3}$ = $\frac{-3}{4}$

6 0

3 years ago

What is the range of possible sizes for side x 2.5 8.0

Vinil7 [7]

Answer:

Let

and

8.5

Let the angle between

and

Let the unknown side be

→

0.5

→

180

∘

→

16.5

So the lenght of side

will be in the interval:

0.5

16.6

Step-by-step explanation:

6 0

3 years ago

Express the number 0.00001038 in scientific notation

In-s [12.5K]

For this case it is observed that the "zeros" are to the left of the expression, therefore the exponent, to be expressed in scientific notation, will be negative. That is to say:

$10.38 * 10^ {- 6}$

This means that by running the decimal 6 spaces to the left we will get the initial expression.

ANswer:

$10.38 * 10^{ - 6}$

4 0

3 years ago

The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}$

$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
-------------------------------\\\\a(2)=\cfrac{215~ft^2}{44~sec}$

8 0

3 years ago

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