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Fittoniya [83]
4 years ago
9

A teacher calculates the class average on an exam for each of his four classes and finds that the means are equal. Which stateme

nt below would lead to believe that this teacher was most pleased with the exam scores in his period 1 class?
A. The scores for period 1 had the lowest median.
B. The scores for period 1 had the highest median.
C. The scores for period 1 had the lowest standard deviation.
D. The scores for period 1 had the lowest IQR.
Mathematics
2 answers:
SpyIntel [72]4 years ago
7 0

<u>Correct Answer:</u> C) The scores for period 1 had the lowest standard deviation.

I just did the assignment, trust me.

hodyreva [135]4 years ago
6 0

<em>Answer:</em>

<em>The scores for period 1 had the highest median.</em>

<em>Step-by-step explanation:</em>

<em>The median is the middle score.</em>

<em>Thus if the class had the highest median, it would mean that more scores are higher, that there are more high scores, than the other classes. </em>

<em />

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Answer:

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1.         1.743 x 10⁻²

2.        3.626 x 10⁻²

3.        4.64 x 10⁻²

4.        3.162 x 10²

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Step-by-step explanation:

The solutions of the mathematical expression are calculated as follows;

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2. \ \ (2.9\times 10^7)(1.6\times 10^{-9}) = (2.9\times 1.6\times 10^{7-9}) = 4.64\times 10^{-2}

3. \ \ \frac{(4.7 \times 10^3)(8.6\times 10^{-7})}{(3.8\times 10^{-4})(6.1 \times 10^2)} = \frac{(4.7\times 8.6\times 10^{3-7})}{(3.8\times 6.1\times 10^{-4+2})} = \frac{4.042 \times 10^{-3}}{2.318\times 10^{-1}} = 1.743\times 10^{-2}

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Arranging the solutions from the least to the highest;

1.         1.743 x 10⁻²

2.        3.626 x 10⁻²

3.        4.64 x 10⁻²

4.        3.162 x 10²

5.        4.214 x 10³

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4 years ago
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Answer:

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