You can write this in a proportion way: 6/55 = x/44.
Multiply both sides by 11 to get rid of the 55 and 44: 6/5 = x/4
Now, multiply both sides by 20: 5x = 24. x = 4.8
Therefore, he can run 4.8 miles in 44 minutes.
Answer:
100/2048=0.048828125%
Step-by-step explanation:
He has a 50% chance of making each free-throw, so 1/2*1/2*1/2*1/2*1/2*1/2*1/2*1/2*1/2*1/2*1/2=1/(2^11)=1/2048
to get a percentage you time by 100 to get 100/2048
Answer:
Step-by-step explanation:
x^2 + 1 -2x + 5
x^2 - 2x + 6
Answer:
Rule: replace x by x - a where a is the number of units that you want to move right. a must be greater than 0. x - - a would move left.
Step-by-step explanation:
You want f(x) to move 3 units to the right.
That would mean that x would be replaced by x - 3. Just to be sure let's try it.
- Suppose you have f(x) = x^2 + 6x + 5 It is graphed as the red line
- Now suppose you want to move 3 units right.
- It would replaced like f(x - 3) = (x - 3)^2 + 6(x - 3) + 5 which is the blue line
- Notice nothing else is changed. The blue line looks exactly like the red line except that it is shifted 3 units to the right.
Answer with step-by-step explanation:
The way the question is worded, this actually shouldn't be correct. The correct answer should be .
Because the trapezoids are similar, we can find the ratio of their perimeters by actually just finding the ratio of their sides.
Why?
By definition, the corresponding sides of a polygon are in a constant proportion. The perimeter is simply the sum of all sides of the polygon. Since we're just adding the sides, the proportion will still be maintained.
Therefore, we'll just need to ratio of their corresponding sides. The only two corresponding sides that are marked are and .
The ratio of is .
The reason why it ideally should be and not is because the question states , which mentions first, so our answer should follow this respective order. I believe you were marked right anyways because the specific order is not specified, but generally, you want to give your answer respectively by default.