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frez [133]
3 years ago
10

Solve for pi : C = 2 pi r. (1 point)

Mathematics
2 answers:
Margarita [4]3 years ago
7 0
C=2πr
Divide by 2r
c/2r=pi
So pi equals c over quantity 2 times r
N76 [4]3 years ago
6 0

Answer:

pie = C over 2r

Step-by-step explanation:

easy answer

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Solve ~<br><img src="https://tex.z-dn.net/?f=2x%20%2B%201%20-%204x%20%3D%207x%20%2B%205" id="TexFormula1" title="2x + 1 - 4x = 7
riadik2000 [5.3K]

Answer:

x=-\frac{4}{9}

Step-by-step explanation:

2x + 1 - 4x = 7x +5

First, take 7x to the left side.

2x + 1 - 4x - 7x = 5

Now take 1 to the right side.

2x - 4x - 7x = 5 - 1

Now combine like terms.

-2x - 7x = 4

-9x = 4

Now divide both sides by -9.

<u>x = - 4/9</u>

7 0
1 year ago
Read 2 more answers
Solve for x. Enter the solutions from least to greatest.
Len [333]

Answer:

This is the answer of your question ☺☺

Step-by-step explanation:

(x+7)2 -49=0

2x+14-49=0

2x-35=0

2x=35

x=17.5

7 0
2 years ago
A container holds 16 quarts of lemonade. How much is this in gallons?
asambeis [7]
4 gallons. 16 divided by 4
5 0
3 years ago
(-9x2 - 4x) + (9x² + 3x + 10)
iogann1982 [59]

Answer:

-x + 10

Step-by-step explanation:

-9x^{2} + 4x + 9x^{2} + 3x + 10

Collect like terms = -1x + 10 OR -x + 10

4 0
3 years ago
Parametric Equation: Find the area enclosed by the x-axis and the curve x=1+e^t, y=t-t^2. Need help with the equation for area.
suter [353]
 <span>I am assuming that this is a parametric curve. 

We see that the curve intersects the x-axis when: 
t - t^2 = 0 ==> t = 0 and t = 1. 

Then, since x = 1 + e^t is an increasing function, the curve is being traced exactly once on the interval (0, 1). 

Using the fact that the area under the curve given by the parametric equations x = f(t) and y = g(t) on (a, b) is: 
A = ∫ f'(t)g(t) dt (from t=a to b), 

and that f(t) = 1 + e^t ==> f'(t) = e^t, the area under the curve is: 
A = ∫ e^t(t - t^2) dt (from t=0 to 1) 
= e^t(-t^2 + 3t - 3) (evaluated from t=0 to 1), by integrating by parts 
= e(-1 + 3 - 3) - (0 + 0 - 3) 
= 3 - e. </span>
5 0
3 years ago
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