From the given diagram <msr is a right angle (equal to 90 degrees) and <mrh is acute since it is less than 90degrees.
<h3>Properties ofa rhombus</h3>
The given diagram is a rhombus that has the following properties
- Opposite side are equal
- All the sides are congruent
- The opposite angles are equal
- The sum of the adjacent angles are supplementary
From the figure shown, we can see that;
<msr is a right angle (equal to 90 degrees)
<mrh is acute since it is less than 90degrees.
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Answer:
The surface area is equal to 
Step-by-step explanation:
The surface area of the triangular pyramid is equal to the area of its four triangular faces
so
In this problem
![SA=4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=SA%3D4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
we have


substitute the values
![SA=4[\frac{1}{2}(15)(13)]=390\ in^{2}](https://tex.z-dn.net/?f=SA%3D4%5B%5Cfrac%7B1%7D%7B2%7D%2815%29%2813%29%5D%3D390%5C%20in%5E%7B2%7D)
Answer:
18/36 or 1/2
Step-by-step explanation:
There are 18 nickels, which is the numerator.
You add all the numbers together to get the denominator, which is 12+6+18=36.
Then, you put the two values in a fraction - 18/36
and simplify, to get you 1/2.
Answer:
4x2 - 9x - 8
Step-by-step explanation:
Answer:
<h2>
cos (α + β) = 0.9196</h2>
Step-by-step explanation:
Given sin α = –4∕5 and sin β = 1∕2
To get α from sin α = –4∕5,
α = arcsin(-4/5)
α = arcsin (-0.8)
α = -53.13°
If angle α is in quadrant III, then α = 180+53.13 = 233.13° (sin is negative in the 3rd quadrant)
Similarly for sin β = 1∕2
β = arcsin(1/2)
β = arcsin(0.5)
β = 30°
Since β is in quadrant II, β = 180-30 = 150°
To find cos (α + β). where α = 233.13° and β = 30°
cos (α + β)= cos (233.13 + 150)
= cos 383.13°
cos (α + β) = 0.9196