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Elden [556K]
2 years ago
10

A maze at a county fair is made from 275 bales of hay.the maze at the state fair is made from 4 times as many bales of hay.how m

any bales of hay are used for the maze at the state fair?
Mathematics
2 answers:
Harlamova29_29 [7]2 years ago
7 0
The calculator said it was "1100"
eduard2 years ago
3 0
1100 bales of hay arr used for the maze at the state fair.
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Solve the equation below for x.<br> x – 15.2 = 76
Amanda [17]

Answer:

91.2

Step-by-step explanation:

add to both sides 15.2 so 76+15.2=91.2

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2 years ago
Please help with this and explain how to do it, I'll give 15 points
MrRissso [65]

Answer:

Option (4).

Step-by-step explanation:

Outer diameter of the hollow metallic ball = 10 centimeters

Outer radius of this ball = \frac{10}{2} = 5 cm

Volume of the outer ball V_{1} = \frac{4}{3}\pi (r)^3

                                         = \frac{4}{3}\pi (5)^3

Inner radius of the hollow metallic ball = (5 - 1) = 4 cm

Volume of the inner hollow ball V_{2} = \frac{4}{3}\pi (4)^3

Volume of the metal used in the metallic ball = V_{1}-V_{2}

                                                                           = \frac{4}{3}\pi (5)^3-\frac{4}{3}\pi (4)^{3}

                                                                           = \frac{4}{3}\pi [(5)^3-(4)^3]

Therefore, expression given in option (4) will be used to measure the volume of the hollow metallic ball.

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3 years ago
PicnicTech markets three versions of its Picnic Egg Boxes: the Golden Deluxe, containing 3 gold eggs and one plain egg; the Regu
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In this line of circles, the ratio of red circles to blue circles is 1:3 How many more circles would need to be added to make th
zaharov [31]

Answer:

The number of red circles to be added would be equal to 8 times the original amount of red circles

Step-by-step explanation:

Let

x ----> the number of red circles

y ----> the number of blue circles

Originally

\frac{x}{y}=\frac{1}{3}

y=3x ----> equation A

How many more circles would need to be added to make the ratio of red to blue 3:1

Let

n ----> the  number of additional red circles

\frac{x+n}{y}=\frac{3}{1} ----> equation B

substitute equation A in equation B

\frac{x+n}{3x}=\frac{3}{1}

solve for n

x+n=9x\\n=9x-x\\n=8x

therefore

The number of red circles to be added would be equal to 8 times the original amount of red circles

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